Math Problem Statement

If∣$A∣=8$ and $|B∣=5$ with $∣A∩B∣=3$, then $|A \cup B|$ = ____.1

Solution

To find AB|A \cup B|, we use the principle of inclusion-exclusion:

AB=A+BAB|A \cup B| = |A| + |B| - |A \cap B|

Given values:

  • A=8|A| = 8
  • B=5|B| = 5
  • AB=3|A \cap B| = 3

Substituting these values:

AB=8+53=10|A \cup B| = 8 + 5 - 3 = 10

Final Answer:

10\boxed{10}

Would you like a breakdown of the principle of inclusion-exclusion?

Here are some related questions:

  1. How do we calculate ABC|A \cup B \cup C| if a third set CC is included?
  2. What happens if AA and BB are disjoint? How does AB|A \cap B| affect the result?
  3. How can we use Venn diagrams to visualize set operations?
  4. If A=x|A| = x, B=y|B| = y, and AB=z|A \cap B| = z, how do we derive the formula?
  5. Can this formula be extended to infinite sets?

Tip: Always check if two sets are disjoint before applying the formula—if they are, AB=0|A \cap B| = 0, simplifying calculations!

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Math Problem Analysis

Mathematical Concepts

Set Theory
Principle of Inclusion-Exclusion

Formulas

|A ∪ B| = |A| + |B| - |A ∩ B|

Theorems

Inclusion-Exclusion Principle

Suitable Grade Level

Grades 7-9