Math Problem Statement

If n(A∩B) = 50, n(A∩Bc) = 200, n(Ac∩B) = 150, what is n(A∪B)?

Solution

To find n(AB)n(A \cup B), which represents the number of elements in the union of sets AA and BB, we will use the information provided:

  • n(AB)=50n(A \cap B) = 50: Number of elements in both AA and BB.
  • n(ABc)=200n(A \cap B^c) = 200: Number of elements in AA but not in BB (here, BcB^c represents the complement of BB).
  • n(AcB)=150n(A^c \cap B) = 150: Number of elements in BB but not in AA (here, AcA^c represents the complement of AA).

Step-by-Step Solution

The total number of elements in the union of AA and BB is given by:

n(AB)=n(AB)+n(ABc)+n(AcB)n(A \cup B) = n(A \cap B) + n(A \cap B^c) + n(A^c \cap B)

Substitute the given values:

n(AB)=50+200+150n(A \cup B) = 50 + 200 + 150

Calculate the sum:

n(AB)=400n(A \cup B) = 400

Conclusion

The number of elements in the union of sets AA and BB is:

400\boxed{400}

Would you like more details or have any questions?

Related Questions

  1. How would you calculate n(AB)n(A \cup B) if you were given n(A)n(A) and n(B)n(B) instead?
  2. How do you determine n(AcBc)n(A^c \cup B^c) using the information given?
  3. What is the relationship between n(AB)n(A \cup B) and n(AcBc)n(A^c \cap B^c)?
  4. How would n(AB)n(A \cup B) change if n(ABc)n(A \cap B^c) were 300 instead of 200?
  5. What formula would you use if you wanted to find n(ABc)+n(AcBc)n(A \cap B^c) + n(A^c \cap B^c)?

Tip: When working with set operations, always consider using Venn diagrams to visualize the different regions, which can help make complex problems more manageable.

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Math Problem Analysis

Mathematical Concepts

Set theory
Union of sets
Complement of sets

Formulas

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Theorems

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Suitable Grade Level

Grades 10-12