Math Problem Statement

The problem involves set theory with operations like union, intersection, symmetric difference, and complement. The sets A, B, C, and S are defined, and three specific operations are required: (1) (A ⊕ B) - C, (2) (B ∪ C)ᶜ, (3) (A ∩ C) - (B ⊕ C).

Solution

Let's break down the content in the image step by step. The problem is presented in the context of set theory with specific sets and operations.

Definitions of the Sets:

  • S={x1x10,xN}S = \{ x \mid 1 \leq x \leq 10, x \in \mathbb{N} \}

    • This means SS is the set of natural numbers between 1 and 10, inclusive: S={1,2,3,4,5,6,7,8,9,10}S = \{1, 2, 3, 4, 5, 6, 7, 8, 9, 10\}
  • A={x1x<10,x is an odd number}A = \{ x \mid 1 \leq x < 10, x \text{ is an odd number} \}

    • AA is the set of odd natural numbers between 1 and 9: A={1,3,5,7,9}A = \{1, 3, 5, 7, 9\}
  • B={x1x<7,x is prime}B = \{ x \mid 1 \leq x < 7, x \text{ is prime} \}

    • BB is the set of prime numbers less than 7: B={2,3,5}B = \{2, 3, 5\}
  • C={2,3,8,10}C = \{2, 3, 8, 10\}

    • CC is a set explicitly given as: C={2,3,8,10}C = \{2, 3, 8, 10\}

Problems:

(1) (AB)C(A \oplus B) - C

  • \oplus refers to the symmetric difference, meaning: AB=(AB)(AB)A \oplus B = (A \cup B) - (A \cap B) First, compute ABA \cup B and ABA \cap B:

    • AB={1,3,5,7,9,2}={1,2,3,5,7,9}A \cup B = \{1, 3, 5, 7, 9, 2\} = \{1, 2, 3, 5, 7, 9\}
    • AB={3,5}A \cap B = \{3, 5\} So, AB=(AB)(AB)={1,2,7,9}A \oplus B = (A \cup B) - (A \cap B) = \{1, 2, 7, 9\}.

    Now, subtract CC from this result: (AB)C={1,2,7,9}{2,3,8,10}={1,7,9}(A \oplus B) - C = \{1, 2, 7, 9\} - \{2, 3, 8, 10\} = \{1, 7, 9\}

(2) (BC)c(B \cup C)^c

  • The complement (BC)c(B \cup C)^c means the elements in SS that are not in BCB \cup C. First, compute BCB \cup C: BC={2,3,5,8,10}B \cup C = \{2, 3, 5, 8, 10\} Now, the complement relative to SS: (BC)c=S(BC)={1,4,6,7,9}(B \cup C)^c = S - (B \cup C) = \{1, 4, 6, 7, 9\}

(3) (AC)(BC)(A \cap C) - (B \oplus C)

  • First, calculate ACA \cap C and BCB \oplus C:

    • AC={2,3,8,10}{1,3,5,7,9}={3}A \cap C = \{2, 3, 8, 10\} \cap \{1, 3, 5, 7, 9\} = \{3\}
    • BC=(BC)(BC)={2,3,5,8,10}{2,3}={5,8,10}B \oplus C = (B \cup C) - (B \cap C) = \{2, 3, 5, 8, 10\} - \{2, 3\} = \{5, 8, 10\}

    Now, subtract BCB \oplus C from ACA \cap C: (AC)(BC)={3}{5,8,10}={3}(A \cap C) - (B \oplus C) = \{3\} - \{5, 8, 10\} = \{3\}

Summary of Results:

  1. (AB)C={1,7,9}(A \oplus B) - C = \{1, 7, 9\}
  2. (BC)c={1,4,6,7,9}(B \cup C)^c = \{1, 4, 6, 7, 9\}
  3. (AC)(BC)={3}(A \cap C) - (B \oplus C) = \{3\}

Would you like further details or explanations on any part of this?

Here are some follow-up questions to expand your understanding:

  1. How would the results change if AA or BB included more elements?
  2. Can you explain the difference between union, intersection, and symmetric difference?
  3. How would you find the complement of a set if the universal set were larger?
  4. What is the significance of prime numbers in the context of set BB?
  5. How would the results change if CC had fewer elements?

Tip: When solving set operations, always compute smaller components like union and intersection first to simplify the overall calculation.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Symmetric Difference
Union
Intersection
Complement

Formulas

Symmetric Difference: A ⊕ B = (A ∪ B) - (A ∩ B)
Set Complement: Aᶜ = S - A (where S is the universal set)

Theorems

-

Suitable Grade Level

Grades 9-12