Math Problem Statement

Let S = {Barnsley, Arsenal, Shildon, Sheffield United, West Ham United, Maroka Swallows, Bidvest Wits, Orlando Pirates, Dumbarten, Lyon} be a universal set. A = {Shildon, West Ham United, Maroka Swallows, Orlando Pirates}, and B = {Barnsley, Arsenal, Shildon}. Find the number indicated: n(A' ∩ B').

Solution

It seems like you've uploaded an image of a mathematical set problem. The question is asking to find the number of elements in a set operation involving complements and intersections.

To analyze the problem:

  • Universal set SS = {Barnsley, Arsenal, Shildon, Sheffield United, West Ham United, Maroka Swallows, Bidvest Wits, Orlando Pirates, Dumbarten, Lyon}
  • Set AA = {Shildon, West Ham United, Maroka Swallows, Orlando Pirates}
  • Set BB = {Barnsley, Arsenal, Shildon}

The task is to find the value of n(AB)n(A' \cap B'), where:

  • AA' is the complement of set AA, meaning all elements in the universal set that are not in AA.
  • BB' is the complement of set BB, meaning all elements in the universal set that are not in BB.
  • ABA' \cap B' represents the intersection of AA' and BB', which includes the elements that are in neither AA nor BB.

Let's calculate it step-by-step.

  1. Find AA': The complement of AA contains all elements from SS except those in AA, i.e. A={Shildon, West Ham United, Maroka Swallows, Orlando Pirates}A = \{ \text{Shildon, West Ham United, Maroka Swallows, Orlando Pirates} \}. So, A={Barnsley, Arsenal, Sheffield United, Bidvest Wits, Dumbarten, Lyon}A' = \{ \text{Barnsley, Arsenal, Sheffield United, Bidvest Wits, Dumbarten, Lyon} \}.

  2. Find BB': The complement of BB contains all elements from SS except those in BB, i.e. B={Barnsley, Arsenal, Shildon}B = \{ \text{Barnsley, Arsenal, Shildon} \}. So, B={Sheffield United, West Ham United, Maroka Swallows, Bidvest Wits, Orlando Pirates, Dumbarten, Lyon}B' = \{ \text{Sheffield United, West Ham United, Maroka Swallows, Bidvest Wits, Orlando Pirates, Dumbarten, Lyon} \}.

  3. Find ABA' \cap B': The intersection of AA' and BB' includes the elements that are common to both AA' and BB'. These elements are:
    AB={Sheffield United, Bidvest Wits, Dumbarten, Lyon}A' \cap B' = \{ \text{Sheffield United, Bidvest Wits, Dumbarten, Lyon} \}.

  4. Count the number of elements in ABA' \cap B':
    There are 4 elements in the intersection.

Thus, n(AB)=4n(A' \cap B') = 4.

Let me know if you need more details or clarifications on any part of this!

Additional Questions:

  1. What does the complement of a set represent in set theory?
  2. How do you calculate the union and intersection of two sets?
  3. What are some real-world applications of set theory?
  4. How do you interpret the cardinality of a set?
  5. Can you compute the union of AA and BB for this example?

Tip: Always start by clearly identifying the universal set and the elements in the sets you’re working with to avoid mistakes in complement calculations.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Complement of a Set
Intersection of Sets

Formulas

A' = S - A
B' = S - B
A' ∩ B' = Elements in both A' and B'

Theorems

Set Complement Theorem
Intersection Properties

Suitable Grade Level

Grades 9-12