Math Problem Statement
Solution
The problem you provided asks to show that for all sets , , and , the following identity holds:
This is a well-known set theory identity that we can prove by showing that each side of the equation is a subset of the other.
Proof:
1. Show that :
Let . This means that is either in or in both and . We consider two cases:
- If , then clearly and , so .
- If , then and . Hence, and , so .
Thus, in both cases, . Therefore, we have shown that:
2. Show that :
Let . This means that and . We consider two cases:
- If , then clearly because .
- If , then must be in both and (since implies , and implies ). Therefore, , and so .
Thus, in both cases, . Therefore, we have shown that:
Conclusion:
Since we have shown both and , we conclude that:
This completes the proof.
Do you have any questions or would you like more details on any step of this proof?
Here are five related questions you might find interesting:
- How do you prove other set theory identities, like De Morgan's laws?
- What are the key differences between union and intersection in set theory?
- Can you extend this result to more than three sets? How would that change the proof?
- How do Venn diagrams help in visualizing set theory proofs like this one?
- How is this identity used in probability theory?
Tip: When working with sets, always break down the proof into cases to carefully handle each part of the set operations (e.g., union, intersection). This ensures clarity in your reasoning.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Union
Intersection
Formulas
A ∪ (B ∩ C) = (A ∪ B) ∩ (A ∪ C)
Theorems
Distributive Law in Set Theory
Suitable Grade Level
Undergraduate Mathematics or Advanced High School (Grades 11-12)