Math Problem Statement

Solve exercises related to sets, including set-builder notation, subset determination, and set equality from the given problems.

Solution

Let’s break down the exercises from your uploaded image.


Exercise 2:

Use set-builder notation to describe the sets:

a) {0, 3, 6, 9, 12}

This set contains multiples of 3, starting from 0 up to 12. In set-builder notation: {xN  x=3n, nN and 0x12}\{ x \in \mathbb{N} \ | \ x = 3n, \ n \in \mathbb{N} \text{ and } 0 \leq x \leq 12 \} where N\mathbb{N} is the set of natural numbers.

b) {-3, -2, -1, 0, 1, 2, 3}

This set contains integers between -3 and 3 (inclusive). In set-builder notation: {xZ  3x3}\{ x \in \mathbb{Z} \ | \ -3 \leq x \leq 3 \} where Z\mathbb{Z} is the set of integers.


Exercise 3:

Determine whether the pairs of sets are equal:

a) {1, 3, 3, 3, 5, 5, 5, 5, 5} and {5, 3, 1}

Yes, these sets are equal because sets ignore duplicates and order. Both simplify to: {1,3,5}.\{1, 3, 5\}.

b) {{1}} and {1, {1}}

No, these sets are not equal. The first set contains only one element, {1}\{1\}, while the second set contains two elements: 11 and {1}\{1\}.

c) \emptyset and {}\{\emptyset\}

No, these sets are not equal. The first set is the empty set with no elements, while the second set contains one element, which is the empty set.


Exercise 4:

Determine subsets:

Sets given: A={2,4,6}, B={2,6}, C={4,6}, D={4,6,8}.A = \{2, 4, 6\}, \ B = \{2, 6\}, \ C = \{4, 6\}, \ D = \{4, 6, 8\}.

  1. BAB \subseteq A: True (all elements of BB are in AA).
  2. CAC \subseteq A: True (all elements of CC are in AA).
  3. DAD \subseteq A: False (8A8 \notin A).

Additionally:

  • BDB \subseteq D: False (2D2 \notin D).
  • CDC \subseteq D: True (all elements of CC are in DD).

Exercise 5:

Determine if 2 or {2}\{2\} is an element of the set:

a) {xR:x is an integer greater than 1}\{x \in \mathbb{R} : x \text{ is an integer greater than 1}\}

  • 2set2 \in \text{set}, because 22 is an integer greater than 1.
  • {2}set\{2\} \notin \text{set}, because {2}\{2\} is not an integer.

b) {xR:x is the square of an integer}\{x \in \mathbb{R} : x \text{ is the square of an integer}\}

  • 2set2 \notin \text{set}, because 22 is not the square of any integer.
  • {2}set\{2\} \notin \text{set}, because {2}\{2\} is not a number.

c) {2,{2}}\{2, \{2\}\}

  • 2set2 \in \text{set}, because 22 is explicitly listed.
  • {2}set\{2\} \in \text{set}, because {2}\{2\} is explicitly listed.

d) {{2},{{2}}}\{\{2\}, \{\{2\}\}\}

  • 2set2 \notin \text{set}, because 22 is not explicitly listed.
  • {2}set\{2\} \in \text{set}, because {2}\{2\} is explicitly listed.

e) {2,{2},{2,{2}}}\{2, \{2\}, \{2, \{2\}\}\}

  • 2set2 \in \text{set}, because 22 is explicitly listed.
  • {2}set\{2\} \in \text{set}, because {2}\{2\} is explicitly listed.

f) {{{2}}}\{\{\{2\}\}\}

  • 2set2 \notin \text{set}, because 22 is not explicitly listed.
  • {2}set\{2\} \notin \text{set}, because {2}\{2\} is not explicitly listed.

Do you need further clarifications or additional explanations?


Related Questions:

  1. How do duplicates and order affect equality in sets?
  2. Can you explain the difference between \emptyset and {}\{\emptyset\} in more detail?
  3. Why is {1}\{1\} different from 11 in a set?
  4. What are the conditions for a set to be a subset of another?
  5. How does set-builder notation vary for different types of numbers?

Tip:

Remember, sets do not care about order or repetition, but they do distinguish between elements and subsets!

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Set Equality
Subsets
Set-Builder Notation

Formulas

Set-Builder Notation: {x | condition on x}
Subset Definition: A ⊆ B if ∀x (x ∈ A → x ∈ B)

Theorems

Equality of Sets: Two sets A and B are equal if A ⊆ B and B ⊆ A
Subset Theorem: If A ⊆ B and A ≠ B, then A is a proper subset of B

Suitable Grade Level

Grades 9-12