Math Problem Statement
Solution
Let's go through each part of the problem using the given sets.
Given:
Now let's calculate each of the following:
a) (Intersection of A and B)
This is the set of elements common to both and . Answer:
b) (Intersection of A and C)
This is the set of elements common to both and . Answer: (the empty set)
c) (Intersection of B and U)
This is the set of elements common to both and the universal set . Since is a subset of , their intersection is itself. Answer:
d) (Complement of relative to U)
First, calculate : The complement of the empty set relative to is itself: Answer:
e) (Union of A and U)
Since is the universal set, the union of and is itself: Answer:
f)
First, find (complement of ): Next, calculate : Now, calculate : Answer:
g) (Cardinality of )
First, find (complement of ): Now, calculate : The cardinality is the number of elements in , which is 2. Answer: 2
h) (Cardinality of )
First, calculate : The cardinality is the number of elements in , which is 9. Answer: 9
Do you have any questions or need further details on any step?
Here are 5 related questions to explore further:
- What is the difference between the union and intersection of sets?
- How is the complement of a set calculated with respect to the universal set?
- How does the cardinality of sets help in determining the size of combined sets?
- What happens when you take the complement of the intersection of two sets?
- How would you represent the symmetric difference between sets A and B?
Tip: The complement of a set contains all elements in the universal set that are not in the original set.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Union
Intersection
Complement
Cardinality
Formulas
A ∩ B = {elements in both A and B}
A ∪ B = {elements in A or B or both}
C' = U - C
Cardinality n(A) = Number of elements in A
Theorems
Basic Set Theory Operations
Suitable Grade Level
Grades 8-10
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