Math Problem Statement

Given that U = {1, 3, 5, 7, 9, 11, 13, 15, 17}, A = {1, 9, 13, 17}, B = {1, 7, 11, 17}, C = {3, 5, 15}. Determine the following: a) A ∩ B, b) A ∩ C, c) B ∩ U, d) (C ∩ A)', e) A ∪ U, f) A ∩ (B ∩ C'), g) n(A ∩ B'), h) n(A ∪ B ∪ C).

Solution

Let's go through each part of the problem using the given sets.

Given:

  • U={1,3,5,7,9,11,13,15,17}U = \{1, 3, 5, 7, 9, 11, 13, 15, 17\}
  • A={1,9,13,17}A = \{1, 9, 13, 17\}
  • B={1,7,11,17}B = \{1, 7, 11, 17\}
  • C={3,5,15}C = \{3, 5, 15\}

Now let's calculate each of the following:

a) ABA \cap B (Intersection of A and B)

This is the set of elements common to both AA and BB. AB={1,9,13,17}{1,7,11,17}={1,17}A \cap B = \{1, 9, 13, 17\} \cap \{1, 7, 11, 17\} = \{1, 17\} Answer: {1,17}\{1, 17\}

b) ACA \cap C (Intersection of A and C)

This is the set of elements common to both AA and CC. AC={1,9,13,17}{3,5,15}=A \cap C = \{1, 9, 13, 17\} \cap \{3, 5, 15\} = \emptyset Answer: \emptyset (the empty set)

c) BUB \cap U (Intersection of B and U)

This is the set of elements common to both BB and the universal set UU. Since BB is a subset of UU, their intersection is BB itself. BU=B={1,7,11,17}B \cap U = B = \{1, 7, 11, 17\} Answer: {1,7,11,17}\{1, 7, 11, 17\}

d) (CA)(C \cap A)' (Complement of CAC \cap A relative to U)

First, calculate CAC \cap A: CA={3,5,15}{1,9,13,17}=C \cap A = \{3, 5, 15\} \cap \{1, 9, 13, 17\} = \emptyset The complement of the empty set relative to UU is UU itself: (CA)=U={1,3,5,7,9,11,13,15,17}(C \cap A)' = U = \{1, 3, 5, 7, 9, 11, 13, 15, 17\} Answer: {1,3,5,7,9,11,13,15,17}\{1, 3, 5, 7, 9, 11, 13, 15, 17\}

e) AUA \cup U (Union of A and U)

Since UU is the universal set, the union of AA and UU is UU itself: AU=U={1,3,5,7,9,11,13,15,17}A \cup U = U = \{1, 3, 5, 7, 9, 11, 13, 15, 17\} Answer: {1,3,5,7,9,11,13,15,17}\{1, 3, 5, 7, 9, 11, 13, 15, 17\}

f) A(BC)A \cap (B \cap C')

First, find CC' (complement of CC): C=UC={1,3,5,7,9,11,13,15,17}{3,5,15}={1,7,9,11,13,17}C' = U - C = \{1, 3, 5, 7, 9, 11, 13, 15, 17\} - \{3, 5, 15\} = \{1, 7, 9, 11, 13, 17\} Next, calculate BCB \cap C': BC={1,7,11,17}{1,7,9,11,13,17}={1,7,11,17}B \cap C' = \{1, 7, 11, 17\} \cap \{1, 7, 9, 11, 13, 17\} = \{1, 7, 11, 17\} Now, calculate A(BC)A \cap (B \cap C'): A{1,7,11,17}={1,9,13,17}{1,7,11,17}={1,17}A \cap \{1, 7, 11, 17\} = \{1, 9, 13, 17\} \cap \{1, 7, 11, 17\} = \{1, 17\} Answer: {1,17}\{1, 17\}

g) n(AB)n(A \cap B') (Cardinality of ABA \cap B')

First, find BB' (complement of BB): B=UB={1,3,5,7,9,11,13,15,17}{1,7,11,17}={3,5,9,13,15}B' = U - B = \{1, 3, 5, 7, 9, 11, 13, 15, 17\} - \{1, 7, 11, 17\} = \{3, 5, 9, 13, 15\} Now, calculate ABA \cap B': AB={1,9,13,17}{3,5,9,13,15}={9,13}A \cap B' = \{1, 9, 13, 17\} \cap \{3, 5, 9, 13, 15\} = \{9, 13\} The cardinality n(AB)n(A \cap B') is the number of elements in {9,13}\{9, 13\}, which is 2. Answer: 2

h) n(ABC)n(A \cup B \cup C) (Cardinality of ABCA \cup B \cup C)

First, calculate ABCA \cup B \cup C: AB={1,9,13,17}{1,7,11,17}={1,7,9,11,13,17}A \cup B = \{1, 9, 13, 17\} \cup \{1, 7, 11, 17\} = \{1, 7, 9, 11, 13, 17\} ABC={1,7,9,11,13,17}{3,5,15}={1,3,5,7,9,11,13,15,17}A \cup B \cup C = \{1, 7, 9, 11, 13, 17\} \cup \{3, 5, 15\} = \{1, 3, 5, 7, 9, 11, 13, 15, 17\} The cardinality n(ABC)n(A \cup B \cup C) is the number of elements in {1,3,5,7,9,11,13,15,17}\{1, 3, 5, 7, 9, 11, 13, 15, 17\}, which is 9. Answer: 9


Do you have any questions or need further details on any step?

Here are 5 related questions to explore further:

  1. What is the difference between the union and intersection of sets?
  2. How is the complement of a set calculated with respect to the universal set?
  3. How does the cardinality of sets help in determining the size of combined sets?
  4. What happens when you take the complement of the intersection of two sets?
  5. How would you represent the symmetric difference between sets A and B?

Tip: The complement of a set contains all elements in the universal set that are not in the original set.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Union
Intersection
Complement
Cardinality

Formulas

A ∩ B = {elements in both A and B}
A ∪ B = {elements in A or B or both}
C' = U - C
Cardinality n(A) = Number of elements in A

Theorems

Basic Set Theory Operations

Suitable Grade Level

Grades 8-10