Math Problem Statement

nomor 19 yang a

Show that if A, B, and C are sets, then A ∩ (B ∩ C)' = A' ∪ (B' ∪ C').

Solution

The problem asks to show that if AA, BB, and CC are sets, then the following equality holds:

A(BC)=A(BC)A \cap (B \cap C)' = A' \cup (B' \cup C')

Part (a): Prove this by showing that each side is a subset of the other.

We'll do this in two parts: first, prove that A(BC)A(BC)A \cap (B \cap C)' \subseteq A' \cup (B' \cup C'), and then prove that A(BC)A(BC)A' \cup (B' \cup C') \subseteq A \cap (B \cap C)'.

Proof 1: A(BC)A(BC)A \cap (B \cap C)' \subseteq A' \cup (B' \cup C')

  1. Let xA(BC)x \in A \cap (B \cap C)'. This means:

    • xAx \in A, and
    • x(BC)x \in (B \cap C)', i.e., xBCx \notin B \cap C.
  2. If xBCx \notin B \cap C, then xBx \notin B or xCx \notin C, meaning:

    • xBCx \in B' \cup C'.
  3. Thus, xAx \in A and x(BC)x \in (B' \cup C'). Therefore, we must show that xA(BC)x \in A' \cup (B' \cup C').

  4. Since xAx \in A, this implies xAx \notin A', so xx belongs to (BC)(B' \cup C').

  5. Therefore, xA(BC)x \in A' \cup (B' \cup C').

Thus, A(BC)A(BC)A \cap (B \cap C)' \subseteq A' \cup (B' \cup C').

Proof 2: A(BC)A(BC)A' \cup (B' \cup C') \subseteq A \cap (B \cap C)'

  1. Let xA(BC)x \in A' \cup (B' \cup C'). This means:

    • Either xAx \in A', or
    • x(BC)x \in (B' \cup C').
  2. If xAx \in A', then xAx \notin A, so xA(BC)x \notin A \cap (B \cap C). Hence, x(BC)x \in (B \cap C)', which means xA(BC)x \in A \cap (B \cap C)'.

  3. If x(BC)x \in (B' \cup C'), this implies xBx \notin B or xCx \notin C, so xBCx \notin B \cap C, which implies x(BC)x \in (B \cap C)'.

  4. Thus, xA(BC)x \in A \cap (B \cap C)'.

Therefore, A(BC)A(BC)A' \cup (B' \cup C') \subseteq A \cap (B \cap C)'.

Conclusion

Since we have shown both A(BC)A(BC)A \cap (B \cap C)' \subseteq A' \cup (B' \cup C') and A(BC)A(BC)A' \cup (B' \cup C') \subseteq A \cap (B \cap C)', we conclude that:

A(BC)=A(BC)A \cap (B \cap C)' = A' \cup (B' \cup C')


Would you like more details or have any questions on this proof?

Here are 5 related questions to expand on this:

  1. How do you prove other set identities, like De Morgan's laws, using subset arguments?
  2. Can you provide an example with specific sets to illustrate the equality?
  3. How do you create a membership table for this proof?
  4. What other techniques are useful in proving set theory identities?
  5. How would the proof change if AA, BB, or CC were empty?

Tip: When proving set equalities, breaking the problem into two parts — showing mutual subset relations — is a reliable approach to establish equality.

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Math Problem Analysis

Mathematical Concepts

Set Theory
Subsets
Union
Intersection
Complement

Formulas

A ∩ (B ∩ C)' = A' ∪ (B' ∪ C')
De Morgan's laws: (A ∩ B)' = A' ∪ B', (A ∪ B)' = A' ∩ B'

Theorems

De Morgan's laws
Set Identities

Suitable Grade Level

Grades 10-12