Math Problem Statement
(AUB) cap (AUB') = A
Solution
Given the expression , let's break it down step-by-step using set theory:
1. Definitions:
- represents the union of sets and .
- represents the union of set with the complement of (where is the complement of ).
- The intersection symbol represents the common elements between the sets.
2. Expression Breakdown:
We need to determine the result of and show that it equals .
Step 1: Expand both unions.
- includes all elements that are in , in , or in both.
- includes all elements that are in , or not in .
Step 2: Consider the intersection.
- The intersection includes all elements that are common to both and .
Step 3: Analyze.
- Any element in will be included in both and , so these elements will definitely be in the intersection.
- For any element not in :
- If is in , it is in , but not in (since it would not be in ).
- If is in , it is in , but not in .
Thus, no elements outside can satisfy both and . Therefore, only the elements of are included in the intersection.
Conclusion:
This shows that the given expression is indeed true.
Would you like more details on this, or do you have any questions?
Related Questions:
- What is the distributive property of sets, and how does it apply to unions and intersections?
- How can Venn diagrams be used to visualize the expression ?
- What is the significance of De Morgan's laws in set theory?
- Can the expression be proven using a Venn diagram or algebraic approach?
- How does the complement operation affect the union and intersection of sets?
Tip:
When working with set theory expressions, try visualizing the sets using Venn diagrams. This often provides clear insights into relationships between the sets.
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Math Problem Analysis
Mathematical Concepts
Set Theory
Union
Intersection
Complement
Formulas
-
Theorems
De Morgan's Laws
Suitable Grade Level
Advanced High School