Math Problem Statement
Solution
We are tasked to determine whether the series
converges or diverges and to justify the conclusion.
Analysis:
-
Behavior of the Term:
- For large , approaches 0.
- Using the Taylor expansion for around 0: \sin(x) \approx x \quad \text{(for small x)}.
- Hence, for large ,
-
Comparison to a Known Series:
- The series is a p-series with , and it converges.
- Since , we suspect converges.
-
Limit Comparison Test:
- Let and .
- Compute:
- For small , , so:
- Since the limit is a positive finite constant (), and converges, the Limit Comparison Test implies also converges.
Conclusion:
The series converges. This conclusion is justified by approximating the terms and applying the Limit Comparison Test.
Do you want a detailed explanation of the Limit Comparison Test or the derivation of the Taylor expansion? Here are related questions to expand on this:
- How does the Taylor series approximation for work, and what are its higher-order terms?
- Why does the series converge, and how does this relate to p-series?
- Can the Direct Comparison Test be applied here instead of the Limit Comparison Test?
- How does the behavior of influence series convergence for different powers of ?
- What happens if we replace with ?
Tip: When approximating terms in series, always check the validity of using asymptotic approximations and whether a formal convergence test is necessary.
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Math Problem Analysis
Mathematical Concepts
Infinite series
Convergence and divergence
Limit comparison test
Taylor series expansion
Formulas
sin(x) ≈ x (for small x)
Limit comparison test: lim (a_n / b_n) as n -> ∞
Theorems
Limit Comparison Test
p-series convergence theorem
Suitable Grade Level
Undergraduate - Calculus II
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