The sequence you provided appears to follow the form:

$\left(1 + \frac{4}{3}\right), \left(1 + \frac{4}{7}\right), \left(1 + \frac{4}{11}\right), \dots, \left(1 + \frac{4}{95}\right)$

This can be described as a sequence where the terms are in the general form:

$a_n = 1 + \frac{4}{4n - 1}$

• The denominator follows the pattern $3, 7, 11, 15, \dots$, which increases by 4 in each step, giving us the sequence of odd multiples of 4 minus 1.

• The $n$-th term can be expressed as:

$a_n = 1 + \frac{4}{4n - 1}$

So for $n = 1$, we get $1 + \frac{4}{3}$, for $n = 2$, we get $1 + \frac{4}{7}$, and so on, until $n = 24$, which gives us $1 + \frac{4}{95}$ (since $4 \times 24 - 1 = 95$).

Would you like further details on this sequence, such as summing the terms or exploring more properties?

Here are five related questions:

1. How do you find the sum of the first 24 terms of this sequence?
2. How does the sequence behave as $n$ increases?
3. What is the general form for any term in sequences with similar patterns?
4. Can this sequence be expressed as a function of $n$ for other values of the numerator (instead of 4)?
5. How do you approach sequences with more complex patterns in the denominator?

Tip: Always look for patterns in the denominators of fractions in sequences; this helps in finding the general term.