The sequence you provided appears to follow the form:

\[
\left(1 + \frac{4}{3}\right), \left(1 + \frac{4}{7}\right), \left(1 + \frac{4}{11}\right), \dots, \left(1 + \frac{4}{95}\right)
\]

This can be described as a sequence where the terms are in the general form:

\[
a_n = 1 + \frac{4}{4n - 1}
\]

- The denominator follows the pattern \(3, 7, 11, 15, \dots\), which increases by 4 in each step, giving us the sequence of odd multiples of 4 minus 1.
  
- The \(n\)-th term can be expressed as:
  
\[
a_n = 1 + \frac{4}{4n - 1}
\]

So for \(n = 1\), we get \(1 + \frac{4}{3}\), for \(n = 2\), we get \(1 + \frac{4}{7}\), and so on, until \(n = 24\), which gives us \(1 + \frac{4}{95}\) (since \(4 \times 24 - 1 = 95\)).

Would you like further details on this sequence, such as summing the terms or exploring more properties?

Here are five related questions:
1. How do you find the sum of the first 24 terms of this sequence?
2. How does the sequence behave as \(n\) increases?
3. What is the general form for any term in sequences with similar patterns?
4. Can this sequence be expressed as a function of \(n\) for other values of the numerator (instead of 4)?
5. How do you approach sequences with more complex patterns in the denominator?

**Tip:** Always look for patterns in the denominators of fractions in sequences; this helps in finding the general term.

The query submitted by the user: [1+4/3] [1+4/7] [1+4/11]....1+4/95

Explore the sequence pattern 1 + 4/3, 1 + 4/7, ... 1 + 4/95 with a general term of a_n = 1 + 4/(4n - 1). Learn how the denominator follows an arithmetic progression and how to express each term. Suitable for high school students, Grades 9-12.

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