Math Problem Statement

Show that the sequence {x_n} defined by x_1 = √7 and x_{n+1} = √(7 + x_n) converges to the positive root of the equation x² - x - 7 = 0.

Solution

The image shows the following problem:


Problem:
Show that the sequence {xn}\{x_n\} defined by
x1=7,xn+1=7+xnx_1 = \sqrt{7}, \quad x_{n+1} = \sqrt{7 + x_n}
converges to the positive root of the equation
x2x7=0.x^2 - x - 7 = 0.


Step-by-Step Explanation:

  1. Find the roots of the equation x2x7=0x^2 - x - 7 = 0:

    • The quadratic equation is given as x2x7=0x^2 - x - 7 = 0.
    • Using the quadratic formula:
    = \frac{1 \pm \sqrt{1 + 28}}{2} = \frac{1 \pm \sqrt{29}}{2}$$ - Therefore, the roots are: $$x = \frac{1 + \sqrt{29}}{2} \quad \text{(positive root)} \quad \text{and} \quad x = \frac{1 - \sqrt{29}}{2} \quad \text{(negative root)}.$$ Since the sequence is defined with square roots, we are interested in the **positive root**: $$x = \frac{1 + \sqrt{29}}{2}.$$
  2. Show that the sequence converges:

    • We need to show that the sequence {xn}\{x_n\}, where xn+1=7+xnx_{n+1} = \sqrt{7 + x_n}, converges to the positive root found above.

    Let's assume the sequence converges to a limit LL. If the sequence converges, then in the limit as nn \to \infty, we have: L=7+L.L = \sqrt{7 + L}. Squaring both sides: L2=7+L.L^2 = 7 + L. Rearranging the terms: L2L7=0.L^2 - L - 7 = 0. This is exactly the equation x2x7=0x^2 - x - 7 = 0, whose positive root we found to be L=1+292L = \frac{1 + \sqrt{29}}{2}.

  3. Conclusion:

    • The sequence {xn}\{x_n\}, defined by x1=7x_1 = \sqrt{7} and xn+1=7+xnx_{n+1} = \sqrt{7 + x_n}, converges to the positive root of the equation x2x7=0x^2 - x - 7 = 0, which is 1+292\frac{1 + \sqrt{29}}{2}.

Would you like to see further details or ask any other questions?

Here are five related questions you might want to explore:

  1. What are the conditions for convergence of a recursive sequence?
  2. How does the initial value x1=7x_1 = \sqrt{7} affect the convergence?
  3. Can this method be generalized to other quadratic equations?
  4. What is the behavior of the negative root of the equation in the context of this sequence?
  5. What are other examples of sequences that converge to a root of an equation?

Tip: To ensure convergence in sequences like this one, check if the recursive relation is a contraction, meaning it brings values closer together as nn increases.

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Math Problem Analysis

Mathematical Concepts

Sequences
Quadratic Equations
Convergence

Formulas

Quadratic formula: x = (-b ± √(b² - 4ac)) / 2a
Recursive sequence relation: x_{n+1} = √(7 + x_n)

Theorems

Quadratic formula
Convergence of recursive sequences

Suitable Grade Level

Grades 10-12