Math Problem Statement

1. (a) Show that the sequence u_n = 1/4 + 1/4^(n+1) is bounded and monotonic. (b) Show that the sequence x_n = (2x_n + 5)/(x_n + 4) converges. 2. (a) Show that x^2 + 2sin(x) = x has at least one solution in the interval [0,1]. (b) Describe the range of the function f(x) = 2 + (q - x) sin(x - π). 3. (a) Find the coordinate point x for which y = (3x)/(x^2 + 1) - x^2 + 4 has a horizontal tangent. (b) Find the differential coefficient of f(x) = 3x sin(2x). 4. (a) Differentiate y = (x + 2)(x + 1)(x + 3)(x + 2). (b) Find f(x) / f'(x) if f(x) = (x^2 + 1)/(x^3 + x^2). (c) Find the derivative of y if y = (x^1.7)/2 - sin(x) + 5/x.

Solution

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Question One: Sequence Convergence and Bounds

  1. (a) Show that the sequence un=14+14n+1u_n = \frac{1}{4} + \frac{1}{4^{n+1}} is bounded and monotonic.

    • Approach: Prove that unu_n is bounded by finding its upper and lower bounds. Then, show it’s monotonic by verifying if un+1unu_{n+1} \leq u_n (monotonically decreasing) or un+1unu_{n+1} \geq u_n (monotonically increasing).
  2. (b) Show that the sequence xn=(2xn+5)/(xn+4)x_n = (2x_n + 5)/(x_n + 4) converges.

    • Approach: Check if xnx_n has a fixed point by solving x=2x+5x+4x = \frac{2x + 5}{x + 4} for xx. Then, determine if xnx_n approaches this value as nn \to \infty.

Question Two: Limits and Function Ranges

  1. (a) Show that x2+2sinx=xx^2 + 2 \sin x = x has at least one solution in the interval [0,1][0, 1].

    • Approach: Use the Intermediate Value Theorem. Evaluate the function at the endpoints of the interval to see if there is a sign change, which indicates a root.
  2. (b) Describe the range of the function f(x)=2+(qx)sin(xπ)f(x) = 2 + (q - x) \sin (x - \pi).

    • Approach: Analyze the behavior of f(x)f(x) based on the value of qq and the periodicity of sin(xπ)\sin(x - \pi).

Question Three: Differentiation and Function Analysis

  1. (a) Find the coordinate point xx for which y=3xx2+1x2+4y = \frac{3x}{x^2 + 1} - x^2 + 4 has a horizontal tangent.

    • Approach: Set the derivative dydx=0\frac{dy}{dx} = 0 and solve for xx.
  2. (b) Find the differential coefficient of f(x)=3xsin2xf(x) = 3x \sin 2x.

    • Approach: Differentiate using the product rule, f(x)=(3x)sin2x+3x(sin2x)f'(x) = (3x)' \sin 2x + 3x (\sin 2x)'.

Question Four: Advanced Differentiation and Integrals

  1. (a) Differentiate y=(x+2)(x+1)(x+3)(x+2)y = (x + 2)(x + 1)(x + 3)(x + 2).

    • Approach: Expand the expression or use the product rule multiple times to differentiate.
  2. (b) Find f(x)/f(x)f(x) / f'(x) if f(x)=x2+1x3+x2f(x) = \frac{x^2 + 1}{x^3 + x^2}.

    • Approach: First find f(x)f'(x) by applying the quotient rule, then divide f(x)f(x) by f(x)f'(x).
  3. (c) Find the derivative of yy if y=x1.72sinx+5xy = \frac{x^{1.7}}{2} - \sin x + \frac{5}{x}.

    • Approach: Differentiate each term separately: use power rule, derivative of sine, and the power rule for x1x^{-1}.

Would you like detailed solutions to any specific question?


Further Questions to Consider

  1. How does the Intermediate Value Theorem guarantee at least one solution in a given interval?
  2. What is the importance of finding fixed points in determining the convergence of sequences?
  3. How do horizontal tangents relate to critical points in calculus?
  4. What role does monotonicity play in ensuring the convergence of sequences?
  5. Can you apply the quotient rule to other functions similar to f(x)=x2+1x3+x2f(x) = \frac{x^2 + 1}{x^3 + x^2}?

Tip:

When differentiating products or quotients, remember to apply the product and quotient rules carefully, ensuring that each step is clearly defined to avoid errors.

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Math Problem Analysis

Mathematical Concepts

Sequences and Series
Limits and Continuity
Differentiation
Function Analysis
Intermediate Value Theorem
Range of Functions

Formulas

u_n = 1/4 + 1/4^(n+1)
x_n = (2x_n + 5)/(x_n + 4)
Intermediate Value Theorem
Horizontal Tangent (dy/dx = 0)
Product Rule for Differentiation
Quotient Rule for Differentiation

Theorems

Intermediate Value Theorem
Monotonic Sequence Theorem
Quotient Rule
Product Rule

Suitable Grade Level

College Level