Math Problem Statement

a^n = [n^2] / [1+n^6]. Is this sequence bounded or unbounded? Is this sequence monotonic or not monotonic? Does this sequence converge or diverge? If the sequence does converge, to what value?

Solution

We are given the sequence:

an=n21+n6a_n = \frac{n^2}{1 + n^6}

We need to analyze whether this sequence is bounded or unbounded, monotonic or non-monotonic, and whether it converges or diverges. If it converges, we also need to find the value to which it converges.

1. Boundedness:

To check if the sequence is bounded, we need to determine if there exists a real number MM such that anM|a_n| \leq M for all nn.

  • For large nn, the denominator 1+n61 + n^6 grows much faster than the numerator n2n^2, so the value of the fraction ana_n tends to decrease as nn increases.

  • Let's check the limit as nn \to \infty:

    limnan=limnn21+n6\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n^2}{1 + n^6} To compute this limit, divide both the numerator and the denominator by n6n^6: limnan=limnn2/n6(1+n6)/n6=limn1/n41+1/n6=0\lim_{n \to \infty} a_n = \lim_{n \to \infty} \frac{n^2 / n^6}{(1 + n^6) / n^6} = \lim_{n \to \infty} \frac{1 / n^4}{1 + 1 / n^6} = 0 Hence, an0a_n \to 0 as nn \to \infty.

    For small values of nn, the sequence ana_n is non-negative and reaches a maximum for small values of nn. Therefore, the sequence is bounded.

2. Monotonicity:

To check whether the sequence is monotonic, we need to check the difference an+1ana_{n+1} - a_n or the ratio an+1an\frac{a_{n+1}}{a_n}.

  • The general form of the sequence is: an=n21+n6a_n = \frac{n^2}{1 + n^6}

  • To determine if it is monotonic, we need to check if ana_n is increasing or decreasing. Consider the derivative of the continuous analogue f(x)=x21+x6f(x) = \frac{x^2}{1 + x^6}:

    f(x)=2x(1+x6)x2(6x5)(1+x6)2=2x6x7(1+x6)2f'(x) = \frac{2x(1 + x^6) - x^2(6x^5)}{(1 + x^6)^2} = \frac{2x - 6x^7}{(1 + x^6)^2} Factorizing: f(x)=2x(13x6)(1+x6)2f'(x) = \frac{2x(1 - 3x^6)}{(1 + x^6)^2} The sign of f(x)f'(x) depends on 13x61 - 3x^6. For small values of xx, f(x)>0f'(x) > 0, so the sequence is increasing for small xx. However, for large xx, f(x)<0f'(x) < 0, meaning the sequence is decreasing for large xx. Hence, the sequence is not monotonic.

3. Convergence:

As we computed earlier: limnan=0\lim_{n \to \infty} a_n = 0 Thus, the sequence converges to 0.

Summary:

  • The sequence is bounded.
  • The sequence is not monotonic.
  • The sequence converges to 0.

Would you like more details on any of these steps or concepts?

5 Related Questions:

  1. How do you prove a sequence is bounded mathematically?
  2. What is the significance of monotonicity in sequence convergence?
  3. How can you find the exact turning point where a sequence stops being monotonic?
  4. Can bounded and non-monotonic sequences still converge?
  5. How does the growth rate of terms in a sequence affect its convergence?

Tip: When checking for boundedness, finding the limit of the sequence as nn \to \infty can provide quick insights into its long-term behavior.

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Math Problem Analysis

Mathematical Concepts

Sequences
Convergence
Monotonicity
Limits

Formulas

a_n = n^2 / (1 + n^6)
Limit formula: lim_{n \to \infty} a_n = 0

Theorems

Boundedness theorem for sequences
Monotonicity of functions
Convergence of sequences

Suitable Grade Level

Undergraduate - Calculus