Math Problem Statement

Topic: Sequence

2. Determine if the sequence is increasing, decreasing, or not monotonic. (a) { (2n - 1) / (4n - 1) } (b) { 3 - 2ne^{-n} } (c) { n^n / n! } 3. Determine if the sequence is bounded. (a) { (1 - n) / (2 + n) } (b) { 2 + (-1)^n / n }

Solution

Let's analyze and solve the problems in the image related to sequences:

Problem 2: Determine if the sequence is increasing, decreasing, or not monotonic.

(a) {2n14n1}\left\{\frac{2n-1}{4n-1}\right\}

We need to check whether the sequence is increasing or decreasing by finding the difference between consecutive terms or evaluating the derivative (for large nn).

  • For large nn, 2n14n1\frac{2n-1}{4n-1} behaves approximately like 24=12\frac{2}{4} = \frac{1}{2}, so the sequence seems to stabilize.
  • To formally check if the sequence is monotonic, we can evaluate the first difference: an+1an=2(n+1)14(n+1)12n14n1a_{n+1} - a_n = \frac{2(n+1)-1}{4(n+1)-1} - \frac{2n-1}{4n-1} This can be simplified to check if the result is positive (increasing) or negative (decreasing).

(b) {32nen}\left\{3 - 2ne^{-n}\right\}

We observe the general behavior of the term 2nen2ne^{-n}:

  • As nn \to \infty, ene^{-n} approaches 0 very quickly, so 2nen02ne^{-n} \to 0.
  • The sequence approaches 33 as nn increases. This suggests the sequence is increasing because 2nen2ne^{-n} decreases with larger nn.

(c) {nnn!}\left\{\frac{n^n}{n!}\right\}

This sequence grows very rapidly because nnn^n increases much faster than n!n!. To determine if it is increasing or decreasing, we could use Stirling's approximation for large nn to approximate both nnn^n and n!n! and check the behavior. This sequence grows extremely fast, indicating it is likely increasing for large nn.


Problem 3: Determine if the sequence is bounded.

(a) {1n2+n}\left\{\frac{1 - n}{2 + n}\right\}

  • For large nn, the sequence behaves like nn=1\frac{-n}{n} = -1.
  • The sequence approaches 1-1 as nn \to \infty, but for small nn, the values will vary.
  • The sequence is bounded because it does not tend to infinity or negative infinity; it is limited by 1-1.

(b) {2+(1)nn}\left\{2 + \frac{(-1)^n}{n}\right\}

  • As nn \to \infty, the term (1)nn\frac{(-1)^n}{n} tends to 0.
  • The sequence oscillates between slightly above and slightly below 2, so it is bounded between 21n2 - \frac{1}{n} and 2+1n2 + \frac{1}{n}.
  • Therefore, the sequence is bounded.

Would you like further details or explanations on any of these sequences?

Here are some follow-up questions to deepen understanding:

  1. How can Stirling's approximation be used to simplify large factorials in sequences?
  2. What is the difference between bounded and monotonic sequences?
  3. How do you prove rigorously whether a sequence is increasing or decreasing?
  4. What are the conditions for a sequence to be unbounded?
  5. How do factorial and exponential terms in sequences affect their growth?

Tip: When analyzing sequences for monotonicity, sometimes it's easier to compare the n+1n+1-th term with the nn-th term directly.

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Math Problem Analysis

Mathematical Concepts

Sequences and Series
Monotonicity
Bounded Sequences
Exponential and Factorial Growth

Formulas

(2n - 1) / (4n - 1)
3 - 2ne^{-n}
n^n / n!
(1 - n) / (2 + n)
2 + (-1)^n / n

Theorems

Monotonicity Theorem
Growth Rate of Factorials and Exponentials

Suitable Grade Level

Undergraduate Mathematics