Math Problem Statement

a semicircular tunnel covers 2 cemented lanes. beyond the lanes are the gutters whose widths of 1ft. each extend up to each of the edges of the tunnel. the maximum height of vehicles that can pass through the tunnel while traveling along the edge of the lane is 4sqrt2 ft. what is the total with(ft.) of the tunnel?

Solution

To solve this problem, let’s break it down step by step:

Step 1: Represent the Semicircular Tunnel

The tunnel is semicircular, so we know that its cross-section resembles a half-circle.

Let:

  • rr be the radius of the tunnel.
  • The total width of the tunnel (diameter) would be 2r2r.

Step 2: Analyze the Given Information

  1. The total width of the lanes and gutters:
    • The problem states that the tunnel covers 2 lanes and 2 gutters.
    • Each lane is cemented and extends between the gutters.
    • The gutters are 1 foot wide each, and the lanes lie between the gutters.

Let's define:

  • ww as the width of one lane.
  • The total width of the lanes and gutters is: Total width=2×1 (gutter width)+2×w (lane width)=2+2w.\text{Total width} = 2 \times 1 \text{ (gutter width)} + 2 \times w \text{ (lane width)} = 2 + 2w.
  1. Vehicle height restriction:
    • The maximum height of vehicles traveling along the edge of the lane (near the gutters) is given as 424\sqrt{2} feet.
    • This means that the vertical distance from the lane’s edge to the top of the tunnel is 424\sqrt{2} feet.

Step 3: Geometry of the Problem

Since the tunnel is semicircular, the relationship between the height of the vehicle and the radius of the tunnel can be analyzed as follows:

  • At a distance of w+1w + 1 feet (from the center of the tunnel to the edge of the lane plus gutter), the height is 424\sqrt{2} feet.

Using the Pythagorean theorem in the right triangle formed by the radius rr, the distance from the center to the edge w+1w + 1, and the height 424\sqrt{2}, we have: r2=(w+1)2+(42)2.r^2 = (w + 1)^2 + (4\sqrt{2})^2. Simplifying the height term: (42)2=16×2=32,(4\sqrt{2})^2 = 16 \times 2 = 32, so the equation becomes: r2=(w+1)2+32.r^2 = (w + 1)^2 + 32.

Step 4: Solving for ww and rr

We still need to find more information to solve for the width ww. However, given the setup of the problem, it's evident that more assumptions or data on the lane width or radius might be needed to compute the total width of the tunnel.


Would you like further details, or do you have any follow-up questions?

Relative Questions:

  1. How can we use the Pythagorean theorem in more complex tunnel shapes?
  2. If the lane width was known, how would we calculate the total tunnel width directly?
  3. What happens if the tunnel was elliptical instead of semicircular?
  4. How does vehicle height affect tunnel design for different types of vehicles?
  5. What role do gutters play in the overall tunnel width calculation?

Tip:

When dealing with semicircular structures, the Pythagorean theorem is often helpful for connecting distances along the radius and height within the structure.

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Math Problem Analysis

Mathematical Concepts

Geometry
Pythagorean Theorem
Radius and Diameter

Formulas

Pythagorean Theorem: a^2 + b^2 = c^2
Relationship between tunnel radius and total width: 2r (Diameter of the semicircle)

Theorems

Pythagorean Theorem

Suitable Grade Level

Grades 10-12