Math Problem Statement

How many ways are there for c and f to sit next to each other and a and b to be opposite

Solution

To solve this problem, we need to determine the number of ways cc and ff can sit next to each other, and aa and bb can sit opposite each other. Let’s break it down step by step:

Assumptions:

  • There are 6 people: a,b,c,d,e,fa, b, c, d, e, f, sitting around a circular table.
  • We treat two seats as "opposite" if they are directly across from each other.

Step-by-step solution:

Step 1: Fix aa and bb opposite each other

Since aa and bb must be opposite each other, we first select two seats for them. In a circular arrangement, fixing the position of one person (say, aa) makes the arrangement linear, and the seat directly opposite is fixed for bb. So there’s only 1 way to arrange aa and bb opposite each other.

Step 2: Treat cc and ff as a block

Since cc and ff must sit next to each other, treat them as a single "block" or "unit." Now, instead of arranging 4 individual people, we are arranging 5 units (the cc-ff block, and the remaining 3 people d,ed, e, and one additional person).

For these 5 units, we can arrange them in 3!3! (factorial) ways, since we have 3 remaining people plus the cc-ff block.

Step 3: Arrange cc and ff within their block

Within the block, cc and ff can sit in 2 ways: either (c,f)(c, f) or (f,c)(f, c).

Total number of arrangements:

  • 1 way to arrange aa and bb opposite each other.
  • 3!3! ways to arrange the 3 remaining people and the cc-ff block: 3!=63! = 6.
  • 2 ways to arrange cc and ff within their block.

Thus, the total number of ways is: 1×6×2=12 ways.1 \times 6 \times 2 = 12 \text{ ways}.

Conclusion:

There are 12 ways for cc and ff to sit next to each other and aa and bb to sit opposite each other.

Do you want further details or explanations?

Here are some related questions:

  1. How would the answer change if it wasn't a circular table?
  2. How many ways are there if dd and ee must sit next to each other instead?
  3. What if aa, bb, and cc need to be in specific seats, but not necessarily opposite?
  4. How many seating arrangements are there if only aa and bb must sit together?
  5. What if cc and ff cannot sit next to each other?

Tip: In circular arrangements, fixing one person's position helps avoid counting equivalent rotations multiple times.

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Math Problem Analysis

Mathematical Concepts

Permutations
Circular Arrangements
Factorials

Formulas

Total arrangements for linear positions = n!
Total arrangements for circular positions = (n-1)!

Theorems

Permutation in Circular Arrangements

Suitable Grade Level

Grades 9-12