The image contains the following mathematical problems:

2.1 A group of 17 friends wants to watch a play one night in a movie theatre. There are 3 rows and 6 seats per row.
2.1.1 Determine in how many different ways they can seat in a row.
2.1.2 One seat (Jabu) is reserved next to each other. Determine the probability that they will sit next to each other.

2.2 Four-digit codes are used to open money vaults in the bank. The code must have two even digits and two odd digits. The even digits must be greater than 4, and without repetition. Determine the number of different codes that can be formed.

Would you like help solving one or both of these problems, or any additional details on them? Let me know, and I'd be happy to assist!

Here are 5 related questions to expand on this:

1. How would the calculation change if the reserved seats for Jabu were not next to each other?
2. Can the arrangement method for the friends be used in other seating problems, like cinema halls with different dimensions?
3. What if the number of digits in the code was 6 instead of 4? How would that affect the possible combinations?
4. Could the probability of Jabu sitting next to each other be calculated using another method, like conditional probability?
5. How do the restrictions on the code (even and odd digits) influence the total number of combinations?

Tip: When calculating combinations, it's important to distinguish between arrangements (permutations) and groupings without regard to order (combinations).