Let's analyze the problem from the image.

You are asked to determine which statements are true about quadrilateral EFGH being a scaled copy of quadrilateral ABCD.

The provided options are:

1. Segment EF is twice as long as segment AB.

   • Looking at the corresponding sides, $EF = 8$ and $AB = 3$. Since $\frac{8}{3} \approx 2.67$, this statement is false because 8 is not exactly twice as large as 3.

2. Segment CD is twice as long as segment FG.

   • Segment $CD = 6$ and segment $FG = 4$. Since $\frac{6}{4} = 1.5$, this statement is false because CD is not twice as long as FG.

3. The measure of angle HEF is twice the measure of angle DAB.

   • In scaled copies, corresponding angles remain the same, not doubled. Therefore, this statement is false.

4. The length of segment EH is 16 units.

   • Based on the diagram, segment $GH = 12$. Since this is a scaled figure, the sides should have a proportional relationship. However, the length of $EH$ is not labeled. This statement seems likely false because it does not match the scaling.

5. The area of EFGH is twice the area of ABCD.

   • Since the scaling factor for lengths between corresponding sides is greater than 2 (as seen with side EF and AB), the area scale factor would be the square of this factor. Therefore, this statement is false because the area of EFGH would be more than twice that of ABCD.

None of the provided statements appear to be true based on the scaling of the quadrilaterals.

Let me know if you would like further clarification, and here are some related questions:

1. How do scaling factors affect areas of geometric shapes?
2. What is the relationship between side lengths and angles in scaled copies?
3. How do you calculate the scale factor between two similar polygons?
4. What happens to the angle measures when you scale a figure?
5. Can a side length be accurately determined from a diagram without explicit labeling?

Tip: When analyzing similar figures, remember that the ratio of areas is the square of the ratio of corresponding side lengths.