Let's solve the given problem step by step.

Given:

• Scale: 1 cm represents 2 m
• Width of the building on the scale drawing: 10 cm
• Real building height: 6.8 m

Part (a):

Find the width of the building in real life.

• Using the scale:
  $\text{Real Width} = \text{Width in drawing} \times \text{Scale factor}$ Substituting values: $\text{Real Width} = 10 \, \text{cm} \times 2 \, \text{m/cm} = 20 \, \text{m}$

Answer for (a): The width of the building in real life is 20 metres.

Part (b):

Find the height of the drawing, in centimetres.

• Using the scale: $\text{Height in drawing} = \frac{\text{Real Height}}{\text{Scale factor}}$ Substituting values: $\text{Height in drawing} = \frac{6.8 \, \text{m}}{2 \, \text{m/cm}} = 3.4 \, \text{cm}$

Answer for (b): The height of the drawing is 3.4 centimetres.

Final Answers:

1. The width of the building in real life is 20 m.
2. The height of the drawing is 3.4 cm.

Would you like further details or clarifications?

Related Questions:

1. What would the width of the building be in real life if the drawing measured 15 cm instead of 10 cm?
2. How would the scale change if 1 cm represented 3 m?
3. What is the area of the real building if its real-life height is 6.8 m and its width is 20 m?
4. How would you calculate the scale if the real-life building width and drawing width were swapped?
5. What is the perimeter of the real building using the given dimensions?

Tip: When solving scale problems, always keep units consistent to avoid errors.