Math Problem Statement

The acceptable level for insect filth in a certain food item is 33 insect fragments​ (larvae, eggs, body​ parts, and so​ on) per 10 grams. A simple random sample of 5050 ​ten-gram portions of the food item is obtained and results in a sample mean of x overbarxequals=3.73.7 insect fragments per​ ten-gram portion. Complete parts ​(a) through ​(c) below. Question content area bottom Part 1 ​(a) Why is the sampling distribution of x overbarx approximately​ normal? A. The sampling distribution of x overbarx is approximately normal because the population is normally distributed. B. The sampling distribution of x overbarx is approximately normal because the population is normally distributed and the sample size is large enough. C. The sampling distribution of x overbarx is assumed to be approximately normal. D. The sampling distribution of x overbarx is approximately normal because the sample size is large enough. Your answer is correct. Part 2 ​(b) What is the mean and standard deviation of the sampling distribution of x overbarx assuming mu equals 3μ=3 and sigmaσequals=StartRoot 3 EndRoot3​? mu Subscript x overbarμxequals=33 ​(Round to three decimal places as​ needed.) Part 3 sigma Subscript x overbarσxequals=0.2450.245 ​(Round to three decimal places as​ needed.) Part 4 ​(c) What is the probability a simple random sample of 5050 ​ten-gram portions of the food item results in a mean of at least 3.73.7 insect​ fragments? ​P(x overbarxgreater than or equals≥3.73.7​)equals=0.00210.0021 ​(Round to four decimal places as​ needed.) Part 5 Is this result​ unusual? A. This result is notis not unusual because its probability is smallsmall. B. This result is notis not unusual because its probability is largelarge. C. This result isis unusual because its probability is largelarge. D. This result isis unusual because its probability is smallsmall.

Solution

Let's go through each part of your problem step by step.

(a) Why is the sampling distribution of xˉ\bar{x} approximately normal?

The correct answer here is:

D. The sampling distribution of xˉ\bar{x} is approximately normal because the sample size is large enough.

This is due to the Central Limit Theorem (CLT), which states that for sufficiently large sample sizes (typically n30n \geq 30), the sampling distribution of the sample mean will be approximately normal, regardless of the population's original distribution. Since the sample size is 50, it meets this criterion.

(b) What is the mean and standard deviation of the sampling distribution of xˉ\bar{x}?

For this part:

  • The mean of the sampling distribution of xˉ\bar{x} is the same as the population mean μ=3\mu = 3.

  • The standard deviation of the sampling distribution of xˉ\bar{x} (also called the standard error) is calculated using the formula: σxˉ=σn\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}} where σ=3\sigma = \sqrt{3} (as given) and n=50n = 50 (sample size).

    σxˉ=350=1.7327.0710.245\sigma_{\bar{x}} = \frac{\sqrt{3}}{\sqrt{50}} = \frac{1.732}{7.071} \approx 0.245

Thus, the mean is 3 and the standard deviation is approximately 0.245.

(c) What is the probability a simple random sample of 50 ten-gram portions of the food item results in a mean of at least 3.7 insect fragments?

To find P(xˉ3.7)P(\bar{x} \geq 3.7), we can standardize this using the z-score formula: z=xˉμσxˉz = \frac{\bar{x} - \mu}{\sigma_{\bar{x}}} Substituting the values:

z=3.730.2450.70.2452.857z = \frac{3.7 - 3}{0.245} \approx \frac{0.7}{0.245} \approx 2.857

Now, using the standard normal distribution table or a calculator, the probability of a z-score of 2.857 or higher is approximately 0.0021. Thus: P(xˉ3.7)0.0021P(\bar{x} \geq 3.7) \approx 0.0021

Is this result unusual?

To determine if this result is unusual, we compare the probability with a typical threshold (commonly, probabilities less than 0.05 or 5% are considered unusual). Since P=0.0021P = 0.0021 is much smaller than 0.05, this event is unusual.

The correct answer is: D. This result is unusual because its probability is small.


Let me know if you need further clarifications! Here are some related questions to consider:

  1. What is the Central Limit Theorem and why is it important?
  2. How is the standard error related to sample size?
  3. What factors affect the shape of the sampling distribution of xˉ\bar{x}?
  4. How would changing the sample size impact the probability found in part (c)?
  5. What would be the z-score if the sample mean were 3.2 instead of 3.7?

Tip: When calculating probabilities from a normal distribution, always standardize the values using z-scores.

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Math Problem Analysis

Mathematical Concepts

Sampling Distribution
Normal Distribution
Central Limit Theorem
Z-score

Formulas

Standard error formula: σ_x = σ / sqrt(n)
Z-score formula: z = (x̄ - μ) / σ_x

Theorems

Central Limit Theorem

Suitable Grade Level

Grades 11-12 (Statistics/Probability)