Math Problem Statement

It is desired to test the null hypothesis μ = 40 against the alternative hypothesis μ > 40 on the basis of a random sample from a population with standard deviation 4. If the probability of a Type I error is to be 0.03 and the probability of Type II error is to be 0.08 for μ = 39, find the required size of the sample.

Solution

To solve this problem, we need to find the required sample size nn for a hypothesis test given specific Type I and Type II error probabilities. Here’s a breakdown of the information provided and the solution steps:

Given Information

  1. Null hypothesis: H0:μ=40H_0: \mu = 40
  2. Alternative hypothesis: H1:μ>40H_1: \mu > 40
  3. Standard deviation of the population (σ\sigma) = 4
  4. Probability of Type I error (significance level, α\alpha) = 0.03
  5. Probability of Type II error (β\beta) = 0.08 for μ=39\mu = 39

Step-by-Step Solution

  1. Determine the Z-scores for Type I and Type II errors using standard normal distribution tables.

    • For α=0.03\alpha = 0.03, the corresponding Z-score (right-tail) is approximately Zα=1.88Z_{\alpha} = 1.88.
    • For β=0.08\beta = 0.08, the corresponding Z-score (left-tail for power calculation) is approximately Zβ=1.41Z_{\beta} = 1.41.
  2. Calculate the Difference in Means:
    Since the alternative hypothesis considers μ>40\mu > 40, we calculate the sample size assuming the mean could be 39 (as specified in the question). The difference in the mean is: Δ=4039=1\Delta = 40 - 39 = 1

  3. Set up the sample size formula:
    The formula for sample size nn when testing for a difference in means is: n=(Zα+ZβΔσ)2n = \left( \frac{Z_{\alpha} + Z_{\beta}}{\frac{\Delta}{\sigma}} \right)^2

    Substituting the values: n=(1.88+1.4114)2n = \left( \frac{1.88 + 1.41}{\frac{1}{4}} \right)^2

  4. Calculate the sample size nn:

    • Calculate the combined Z-score: 1.88+1.41=3.291.88 + 1.41 = 3.29
    • Divide by the standardized effect size: 3.2914=3.29×4=13.16\frac{3.29}{\frac{1}{4}} = 3.29 \times 4 = 13.16
    • Square the result to find nn: n=(13.16)2=173.1856n = (13.16)^2 = 173.1856

    Rounding up (since sample size must be a whole number), we find: n174n \approx 174

Final Answer

The required sample size nn is approximately 174.

Would you like a detailed explanation of each step or have any questions?

Related Questions

  1. How would the required sample size change if the probability of Type I error α\alpha was increased?
  2. How do we determine Z-scores for specific probabilities in hypothesis testing?
  3. What is the impact of a larger standard deviation on sample size requirements?
  4. How would this calculation differ if we were testing H1:μ<40H_1: \mu < 40 instead?
  5. What happens to Type II error probability if the sample size is reduced?

Tip

In hypothesis testing, increasing the sample size reduces the probability of Type II error, increasing the test’s power.

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Math Problem Analysis

Mathematical Concepts

Hypothesis Testing
Sample Size Determination
Type I and Type II Errors

Formulas

Sample size formula for hypothesis testing: n = ((Zα + Zβ) * σ / Δ)^2
Z-score lookup for specific significance levels (α and β)

Theorems

Central Limit Theorem

Suitable Grade Level

College Level