Math Problem Statement
Solution
The text in the image reads:
"5. (a) For the given RSA algorithm. Given , in RSA algorithm, and the ciphertext , find and the plaintext ."
To solve this, let's break it down step-by-step.
Step 1: Understanding RSA Parameters
In the RSA algorithm:
- and are prime numbers used to compute .
- is the Euler's totient function.
- The public key consists of , where is the public exponent.
- The private key consists of , where is the private exponent.
- is calculated as the modular multiplicative inverse of modulo , meaning satisfies the equation .
Step 2: Calculate and
Given:
We compute:
Step 3: Find
We need to find such that: Given , we want:
We need the multiplicative inverse of 3 modulo 20. The value of that satisfies this can be found using the Extended Euclidean Algorithm.
Step 4: Calculate the Multiplicative Inverse of
Using the Extended Euclidean Algorithm, we find that:
Step 5: Decrypt the Ciphertext
Now, to find the plaintext : Given , , and , we calculate:
This is a large calculation, so let's simplify by computing .
Step 6: Simplify Using Modular Exponentiation
Let's compute this step-by-step:
Conclusion
- The private key
- The plaintext
Would you like more details on any step, or do you have any further questions?
Related Questions
- How do you compute the modular multiplicative inverse using the Extended Euclidean Algorithm?
- What is the significance of the public and private keys in RSA encryption?
- Can you provide more examples of decrypting ciphertext using the RSA algorithm?
- How does RSA encryption ensure security in communication?
- What are the practical applications of RSA in today's technology?
Tip
To perform modular exponentiation efficiently, use the "square and multiply" method.
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Math Problem Analysis
Mathematical Concepts
Number Theory
Cryptography
Modular Arithmetic
Formulas
n = p × q
φ(n) = (p - 1)(q - 1)
e × d ≡ 1 mod φ(n)
M = C^d mod n
Theorems
Euler's Totient Function
Modular Multiplicative Inverse
Suitable Grade Level
Undergraduate (Cryptography/Computer Science)
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