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The problem is asking for the equation of the line \( -x + 3y - 15 = 0 \) after it has been rotated 90° clockwise about the origin \( O(0,0) \).

### Steps to solve:
1. **Equation of the line**: The given line is \( -x + 3y - 15 = 0 \), which can be written as \( y = \frac{1}{3}x + 5 \).

2. **General rotation formula**: To rotate a line, we use the parametric point rotation formulas. For a 90° clockwise rotation about the origin, the transformation of any point \( (x, y) \) is:
   \[
   (x', y') = (y, -x)
   \]
   This means every point on the line \( (x, y) \) will map to a new point \( (y, -x) \).

3. **Transforming the equation**: To rotate the entire line, we substitute \( x' = y \) and \( y' = -x \) into the original equation \( -x + 3y - 15 = 0 \).

   Substituting these transformations:
   \[
   -(y') + 3(-x') - 15 = 0
   \]
   Simplifying:
   \[
   -y' - 3x' - 15 = 0
   \]
   This is the equation of the rotated line.

4. **Final equation**: Therefore, the equation of the line after a 90° clockwise rotation is:
   \[
   -y - 3x - 15 = 0 \quad \text{or equivalently} \quad 3x + y + 15 = 0
   \]

Would you like more details on the steps?

Here are 5 related questions you might want to explore:
1. What is the effect of a 90° counterclockwise rotation on the same line?
2. How would you rotate a line by 180° around the origin?
3. Can the general formula for any angle of rotation be applied here?
4. What is the geometric interpretation of rotating a line?
5. How would you graph the original line and the rotated line?

**Tip**: When rotating figures or equations, always use transformation formulas specific to the rotation angle and direction.

Bayangan garis -x + 3y - 15 = 0 jika dirotasikan 90° searah jarum jam dengan pusat O(0,0) adalah...

Learn how to find the equation of the line -x + 3y - 15 = 0 after a 90-degree clockwise rotation around the origin. This problem covers concepts of linear equations and rotation transformations in analytic geometry.

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