The question is about rotating the exponential function $y = 2^x$ by 90° clockwise and determining the coordinates when $x = 3$.

Steps to solve:

1. Find the coordinates before rotation: For $x = 3$, calculate the corresponding $y$ value in the original function $y = 2^x$: $y = 2^3 = 8$ So, the point before rotation is $(3, 8)$.

2. Rotation by 90° clockwise: When a point $(x, y)$ is rotated by 90° clockwise, the new coordinates $(x', y')$ are given by: $(x', y') = (y, -x)$ Applying this to the point $(3, 8)$: $x' = 8, \quad y' = -3$ So, the new coordinates after the rotation are $(8, -3)$.

Conclusion:

The coordinates after the rotation are $(8, -3)$, which matches option C.

Would you like further details or clarification?

Here are 5 related questions:

1. What is the geometric interpretation of rotating a function?
2. How does rotating by 180° affect the coordinates of a point?
3. Can you explain the process of transforming other types of functions, like quadratic functions, under rotations?
4. What happens to the shape of the graph after a 90° clockwise rotation?
5. Can we generalize the rotation formula to any angle, not just 90°?

Tip: When dealing with rotations, it's helpful to visualize the process on a coordinate plane to ensure the transformation makes sense.