Math Problem Statement

How to find roots of complex numbers

Solution

To find the roots of a complex number, we follow the process outlined below, which utilizes polar (or trigonometric) form and De Moivre's Theorem:


Steps to Find Roots of a Complex Number:

  1. Convert the complex number to polar form: A complex number z=a+biz = a + bi can be written in polar form as: z=rcisθz = r \text{cis} \theta where:

    • r=a2+b2r = \sqrt{a^2 + b^2} is the modulus of zz,
    • θ=tan1(ba)\theta = \tan^{-1}\left(\frac{b}{a}\right) is the argument (angle) of zz,
    • cisθ=cosθ+isinθ\text{cis} \theta = \cos \theta + i \sin \theta.
  2. Apply the nth root formula: The nn-th roots of a complex number are given by: zk=r1/ncis(θ+2kπn),k=0,1,2,,n1.z_k = r^{1/n} \text{cis} \left(\frac{\theta + 2k\pi}{n}\right), \quad k = 0, 1, 2, \ldots, n-1. Here:

    • r1/nr^{1/n} is the nth root of the modulus,
    • θ+2kπn\frac{\theta + 2k\pi}{n} are the angles for each root,
    • kk represents the different roots.
  3. Simplify each root: For each kk, compute zkz_k using: zk=r1/n(cosθ+2kπn+isinθ+2kπn).z_k = r^{1/n} \left(\cos \frac{\theta + 2k\pi}{n} + i \sin \frac{\theta + 2k\pi}{n}\right).


Example:

Find the cube roots of z=8z = 8 (purely real).

  1. Write zz in polar form: z=8cis0z = 8 \text{cis} 0 (since 88 is on the real axis with θ=0\theta = 0).

  2. Apply the nth root formula for n=3n = 3: zk=2cis(0+2kπ3),k=0,1,2.z_k = 2 \text{cis} \left(\frac{0 + 2k\pi}{3}\right), \quad k = 0, 1, 2.

  3. Compute the roots:

    • For k=0k = 0: z0=2cis0=2.z_0 = 2 \text{cis} 0 = 2.
    • For k=1k = 1: z1=2cis2π3=2(12+i32).z_1 = 2 \text{cis} \frac{2\pi}{3} = 2 \left(-\frac{1}{2} + i \frac{\sqrt{3}}{2}\right).
    • For k=2k = 2: z2=2cis4π3=2(12i32).z_2 = 2 \text{cis} \frac{4\pi}{3} = 2 \left(-\frac{1}{2} - i \frac{\sqrt{3}}{2}\right).

Thus, the roots are: z0=2,z1=1+i3,z2=1i3.z_0 = 2, \quad z_1 = -1 + i\sqrt{3}, \quad z_2 = -1 - i\sqrt{3}.


Questions to Deepen Understanding:

  1. How is the argument θ\theta calculated for complex numbers not on the real axis?
  2. What changes in the method if the modulus of the complex number is less than 1?
  3. Can you explain how De Moivre's Theorem helps generalize this process?
  4. How would you find the fourth roots of 1+i1 + i?
  5. What happens if kk exceeds n1n-1 in the formula?

Tip: Always sketch the roots on the complex plane to visualize their symmetry. Roots are evenly spaced in a circle centered at the origin.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Polar Form of Complex Numbers
Roots of Complex Numbers

Formulas

Polar form: z = r(cos θ + i sin θ)
Nth root formula: z_k = r^(1/n) cis(θ + 2kπ / n)

Theorems

De Moivre's Theorem

Suitable Grade Level

Grades 11-12