Math Problem Statement

Given a right triangle with hypotenuse AB = 20, one leg AΓ = 15, and the other leg BΓ = x, find the value of x using the Pythagorean theorem.

Solution

The given diagram depicts a right triangle ABΓ\triangle AB\Gamma, with the following information provided:

  • AB=20AB = 20 (hypotenuse),
  • AΓ=15A\Gamma = 15 (one leg),
  • BΓ=xB\Gamma = x (unknown leg).

To find xx, we can apply the Pythagorean theorem, which states: AB2=AΓ2+BΓ2AB^2 = A\Gamma^2 + B\Gamma^2

Steps:

  1. Substitute the known values into the equation: 202=152+x220^2 = 15^2 + x^2

  2. Simplify: 400=225+x2400 = 225 + x^2

  3. Solve for x2x^2: x2=400225=175x^2 = 400 - 225 = 175

  4. Solve for xx: x=175=257=5713.23x = \sqrt{175} = \sqrt{25 \cdot 7} = 5\sqrt{7} \approx 13.23

Final Answer:

x=5713.23x = 5\sqrt{7} \approx 13.23

Would you like a detailed explanation of the steps or any additional clarification?


Related Questions:

  1. How can the Pythagorean theorem be applied in real-world situations?
  2. What are the properties of right triangles in trigonometry?
  3. How can you find the angles in a right triangle using trigonometric ratios?
  4. What are the practical uses of surds (like 7\sqrt{7}) in geometry?
  5. How can one verify the correctness of calculated triangle sides?

Tip: Always verify the largest side of a triangle as the hypotenuse to ensure correct application of the Pythagorean theorem.

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Math Problem Analysis

Mathematical Concepts

Geometry
Right Triangles
Square Roots

Formulas

Pythagorean theorem: c^2 = a^2 + b^2

Theorems

Pythagorean theorem

Suitable Grade Level

Grades 8-10