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This is a right triangle where:

- One leg is 20 units,
- The hypotenuse is 25 units, and
- The remaining side, denoted as \( x \), is what we need to find.

We can use the **Pythagorean Theorem** to solve for \( x \). The theorem states:

\[
a^2 + b^2 = c^2
\]

where \( a \) and \( b \) are the legs of the right triangle, and \( c \) is the hypotenuse.

Here:
- \( a = 20 \) (one leg),
- \( b = x \) (the other leg),
- \( c = 25 \) (the hypotenuse).

Now, applying the Pythagorean Theorem:

\[
20^2 + x^2 = 25^2
\]

This simplifies to:

\[
400 + x^2 = 625
\]

Now, solve for \( x^2 \):

\[
x^2 = 625 - 400 = 225
\]

Finally, take the square root of both sides:

\[
x = \sqrt{225} = 15
\]

Thus, the value of \( x \) is \( \boxed{15} \).

Would you like more details or have any questions about this solution? 

Here are 5 related questions for further practice:
1. What is the length of the hypotenuse if both legs are 9 and 12?
2. If one leg is 7 and the hypotenuse is 25, what is the length of the other leg?
3. Can a triangle with sides 10, 24, and 26 be a right triangle?
4. What is the area of a right triangle with legs 8 and 15?
5. How does the Pythagorean theorem relate to the distance formula in coordinate geometry?

**Tip**: Always double-check units and values when applying the Pythagorean theorem to avoid small calculation errors.

Learn how to find the missing side (x) of a right triangle with one leg 20 units and hypotenuse 25 units using the Pythagorean Theorem. This detailed step-by-step solution is suitable for students in Grades 8-10.

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