Math Problem Statement

Represent f(t) in piecewise fashion as follows:

F(t) = {2t-2 if 3 <= t < 4, 6 if 4 <= t < 8, 0 otherwise.

Represent f(t) in piecewise fashion as follows: F(t) = {2t-2 if 3 <= t < 4, 6 if 4 <= t < 8, 0 otherwise.}

Solution

To represent f(t)f(t) in a piecewise function based on the graph provided, let's analyze the intervals and corresponding values of f(t)f(t):

  1. Interval Analysis:

    • For 3t<43 \leq t < 4: The graph has a slope, suggesting a linear relationship. Observing the points, we can deduce that the line has the form f(t)=2t2f(t) = 2t - 2.
    • For 4t<84 \leq t < 8: The graph is flat, meaning f(t)f(t) is constant. From the graph, f(t)=6f(t) = 6 in this interval.
    • For values outside these intervals (i.e., t<3t < 3 or t8t \geq 8): The function is 0, indicating that f(t)=0f(t) = 0 otherwise.
  2. Piecewise Representation: Given the intervals and values identified, we can represent f(t)f(t) as:

    2t - 2 & \text{if } 3 \leq t < 4, \\ 6 & \text{if } 4 \leq t < 8, \\ 0 & \text{otherwise}. \end{cases}$$

This representation captures the behavior of f(t)f(t) as illustrated in the graph.

Would you like further details on how each part of the piecewise function was determined, or do you have additional questions?

Related Questions

  1. How do you determine the slope of a linear segment on a graph?
  2. Why is the function zero outside the specified intervals?
  3. What are some common applications of piecewise functions?
  4. How can we find the derivative of this piecewise function?
  5. What does continuity mean in the context of piecewise functions?

Tip

When analyzing a graph, observe points of discontinuity or changes in slope to identify distinct intervals in piecewise functions.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Piecewise Functions
Linear Functions
Function Graphing

Formulas

f(t) = 2t - 2 for 3 <= t < 4
f(t) = 6 for 4 <= t < 8
f(t) = 0 otherwise

Theorems

-

Suitable Grade Level

Grades 9-11