Math Problem Statement

Let T be a one-to-one matrix transformation from ℝ^n to ℝ^m. What can one say about the relationship between m and n? A. n > m B. n ≤ m C. n < m D. n < m E. There is not enough information to tell

Solution

The problem provided is about a matrix transformation T:RnRmT: \mathbb{R}^n \to \mathbb{R}^m that is one-to-one (injective). We need to determine the relationship between mm and nn.

Explanation:

A matrix transformation from Rn\mathbb{R}^n to Rm\mathbb{R}^m can be represented by an m×nm \times n matrix. For the transformation to be one-to-one, its kernel must only contain the zero vector. This implies that the columns of the matrix must be linearly independent.

If the matrix has nn columns (since it maps from Rn\mathbb{R}^n), and for the columns to be linearly independent, we must have nmn \leq m. This is because there cannot be more linearly independent vectors in Rm\mathbb{R}^m than the dimension mm itself.

Conclusion:

The correct answer is:

B. nmn \leq m

Would you like more details on this topic, or do you have any other questions?

Related Questions:

  1. What is the difference between injective and surjective transformations?
  2. How can you determine if a matrix transformation is onto (surjective)?
  3. What is the rank of a matrix, and how does it relate to linear independence?
  4. Can a transformation be both injective and surjective? If so, what is it called?
  5. How does the determinant of a matrix relate to its injectivity or surjectivity?

Tip:

To determine if a matrix transformation is injective, you can check if the matrix has a full column rank. If it does, then the transformation is injective.

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Math Problem Analysis

Mathematical Concepts

Linear Algebra
Matrix Transformations
Linear Independence
Injective Transformations

Formulas

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Theorems

Linear Independence
Rank-Nullity Theorem

Suitable Grade Level

Undergraduate (University Level)