Math Problem Statement
Suppose matrix A is m×n, and T : Rn → Rm, where T(x) = Ax.
If for every b ∈ Rm in the range of T, there is at most one x ∈ Rn so that Ax = b, then T must be onto.
Solution
The statement is incorrect. Let's break it down:
Given:
- Matrix is ,
- , defined by .
The condition "for every in the range of , there is at most one such that " is saying that the transformation is injective (one-to-one), meaning there are no two distinct 's that map to the same .
Does injectivity imply surjectivity (onto)?
- Injectivity means that each in the range of has at most one corresponding .
- **Surject
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Math Problem Analysis
Mathematical Concepts
Linear Algebra
Matrix Transformations
Injective and Surjective Functions
Formulas
T(x) = Ax (Linear transformation formula)
Theorems
Injectivity does not imply Surjectivity
Rank-Nullity Theorem
Suitable Grade Level
College-level (Linear Algebra)
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