Math Problem Statement
Question content area top Part 1 Use the data set below to answer the following questions. Complete parts a through d. x 1x1 29 48 28 22 28 42 33 26 48 44
x 2x2 15 37 24 32 47 13 43 12 58 19 y 2020 4040 2929 2727 4141 1414 3535 1515 4141 1313 Question content area bottom Part 1 a. Obtain the estimated regression equation. ModifyingAbove y with caretyequals=nothing plus left parenthesis nothing right parenthesis x 1 plus left parenthesis nothing right parenthesis x 210.810.8+negative 0.1−0.1x1+0.70.7x2 (Round to one decimal place as needed.) Part 2 b. nbspb. Develop the correlation matrix for this set of data. Select the independent variable whose correlation magnitude is the smallest with the dependent variable. Determine if its correlation with the dependent variable is significant. Use alphaαequals=0.050.05. Complete the correlation matrix below. y x 1x1 x 2x2 y 1 x 1x1 0.1560.156 1 x 2x2 0.9160.916 0.2570.257 1 (Round to three decimal places as needed.) Part 3 Select the independent variable whose correlation magnitude is the smallest with the dependent variable. The parameter of interest is the population correlation coefficient between y and x 1x1 . Part 4 Determine the hypotheses. Choose the correct answer below. A. Upper H 0H0: rhoρless than or equals≤0 Upper H Subscript Upper AHA: rhoρgreater than>0 B. Upper H 0H0: rhoρgreater than or equals≥0 Upper H Subscript Upper AHA: rhoρless than<0 C. Upper H 0H0: rhoρequals=0 Upper H Subscript Upper AHA: rhoρnot equals≠0 Your answer is correct.D. Upper H 0H0: rhoρnot equals≠0 Upper H Subscript Upper AHA: rhoρequals=0 Part 5 Calculate the test statistic. tequals=enter your response here (Round to three decimal places as needed.)
Solution
To solve the parts of this question systematically, we will go step by step:
Part 1a: Obtain the estimated regression equation
The general form of the regression equation is:
We use multiple regression formulas to find , , and . The calculations involve finding the coefficients using the least squares method:
Given the provided estimated regression equation:
We already have the coefficients:
- ,
- ,
- .
Part 1b: Develop the correlation matrix
To develop the correlation matrix, we calculate pairwise correlations between the variables (, , ) using the formula:
The correlation matrix is:
1 | 0.156 | 0.916 | |
0.156 | 1 | 0.257 | |
0.916 | 0.257 | 1 |
The independent variable with the smallest correlation magnitude with is ().
Part 1c: Hypothesis testing for
We test whether the correlation coefficient between and () is significant.
- Hypotheses:
- : (no correlation)
- : (correlation exists)
This corresponds to Option C.
Part 1d: Calculate the test statistic
The test statistic for correlation is calculated as:
Where:
- (correlation between and ),
- (sample size).
Substitute values into the formula:
The test statistic is .
Conclusion:
- Based on the -test value and degrees of freedom (), compare the -value with . If , fail to reject ; otherwise, reject .
Do you need further clarification on any step?
Follow-up Questions:
- Would you like to compute the -value and decision for the hypothesis test?
- Should I explain how the correlation matrix is calculated in detail?
- Would you like to understand how the regression coefficients are computed from scratch?
- Do you want a step-by-step analysis of the test statistic formula?
- Should I provide a graph to visualize the correlations?
Tip:
When dealing with multiple regression, always examine the correlation matrix to assess multicollinearity before interpreting regression coefficients.
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Math Problem Analysis
Mathematical Concepts
Regression Analysis
Correlation Analysis
Hypothesis Testing
Multiple Linear Regression
Formulas
Regression Equation: y = b0 + b1x1 + b2x2
Correlation Coefficient: r = Cov(x, y) / sqrt(Var(x) * Var(y))
Test Statistic for Correlation: t = r * sqrt(n - 2) / sqrt(1 - r^2)
Theorems
Least Squares Method
Properties of Correlation Coefficients
Student's t-distribution for Hypothesis Testing
Suitable Grade Level
Undergraduate (Statistics or Econometrics)
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