Math Problem Statement

Question content area top Part 1 Use the data set below to answer the following questions. Complete parts a through d. x 1x1 29 48 28 22 28 42 33 26 48 44

x 2x2 15 37 24 32 47 13 43 12 58 19 y 2020 4040 2929 2727 4141 1414 3535 1515 4141 1313 Question content area bottom Part 1 a. Obtain the estimated regression equation. ModifyingAbove y with caretyequals=nothing plus left parenthesis nothing right parenthesis x 1 plus left parenthesis nothing right parenthesis x 210.810.8+negative 0.1−0.1x1+0.70.7x2 ​(Round to one decimal place as​ needed.) Part 2 b. nbspb. Develop the correlation matrix for this set of data. Select the independent variable whose correlation magnitude is the smallest with the dependent variable. Determine if its correlation with the dependent variable is significant. Use alphaαequals=0.050.05. Complete the correlation matrix below. y x 1x1 x 2x2 y 1 x 1x1 0.1560.156 1 x 2x2 0.9160.916 0.2570.257 1 ​(Round to three decimal places as​ needed.) Part 3 Select the independent variable whose correlation magnitude is the smallest with the dependent variable. The parameter of interest is the population correlation coefficient between y and x 1x1 . Part 4 Determine the hypotheses. Choose the correct answer below. A. Upper H 0H0​: rhoρless than or equals≤0 Upper H Subscript Upper AHA​: rhoρgreater than>0 B. Upper H 0H0​: rhoρgreater than or equals≥0 Upper H Subscript Upper AHA​: rhoρless than<0 C. Upper H 0H0​: rhoρequals=0 Upper H Subscript Upper AHA​: rhoρnot equals≠0 Your answer is correct.D. Upper H 0H0​: rhoρnot equals≠0 Upper H Subscript Upper AHA​: rhoρequals=0 Part 5 Calculate the test statistic. tequals=enter your response here ​(Round to three decimal places as​ needed.)

Solution

To solve the parts of this question systematically, we will go step by step:


Part 1a: Obtain the estimated regression equation

The general form of the regression equation is:

y^=b0+b1x1+b2x2\hat{y} = b_0 + b_1x_1 + b_2x_2

We use multiple regression formulas to find b0b_0, b1b_1, and b2b_2. The calculations involve finding the coefficients using the least squares method:

b1=SSx1ySSx1x1,b2=SSx2ySSx2x2,b0=yˉb1xˉ1b2xˉ2b_1 = \frac{SS_{x_1y}}{SS_{x_1x_1}}, \quad b_2 = \frac{SS_{x_2y}}{SS_{x_2x_2}}, \quad b_0 = \bar{y} - b_1\bar{x}_1 - b_2\bar{x}_2

Given the provided estimated regression equation:

y^=10.80.1x1+0.7x2\hat{y} = 10.8 - 0.1x_1 + 0.7x_2

We already have the coefficients:

  • b0=10.8b_0 = 10.8,
  • b1=0.1b_1 = -0.1,
  • b2=0.7b_2 = 0.7.

Part 1b: Develop the correlation matrix

To develop the correlation matrix, we calculate pairwise correlations between the variables (yy, x1x_1, x2x_2) using the formula:

rxy=Cov(x,y)Var(x)Var(y)r_{xy} = \frac{\text{Cov}(x, y)}{\sqrt{\text{Var}(x) \cdot \text{Var}(y)}}

The correlation matrix is:

yyx1x_1x2x_2
yy10.1560.916
x1x_10.15610.257
x2x_20.9160.2571

The independent variable with the smallest correlation magnitude with yy is x1x_1 (r=0.156r = 0.156).


Part 1c: Hypothesis testing for x1x_1

We test whether the correlation coefficient between yy and x1x_1 (ρ\rho) is significant.

  • Hypotheses:
    • H0H_0: ρ=0\rho = 0 (no correlation)
    • HAH_A: ρ0\rho \neq 0 (correlation exists)

This corresponds to Option C.


Part 1d: Calculate the test statistic

The test statistic for correlation is calculated as:

t=rn21r2t = \frac{r \sqrt{n - 2}}{\sqrt{1 - r^2}}

Where:

  • r=0.156r = 0.156 (correlation between x1x_1 and yy),
  • n=10n = 10 (sample size).

Substitute values into the formula:

t=0.15610210.1562t = \frac{0.156 \cdot \sqrt{10 - 2}}{\sqrt{1 - 0.156^2}}

t=0.156810.0243t = \frac{0.156 \cdot \sqrt{8}}{\sqrt{1 - 0.0243}}

t=0.1562.8280.9757t = \frac{0.156 \cdot 2.828}{\sqrt{0.9757}}

t=0.4410.98780.447t = \frac{0.441}{0.9878} \approx 0.447

The test statistic is t=0.447t = 0.447.


Conclusion:

  1. Based on the tt-test value and degrees of freedom (df=n2=8df = n - 2 = 8), compare the pp-value with α=0.05\alpha = 0.05. If p>αp > \alpha, fail to reject H0H_0; otherwise, reject H0H_0.

Do you need further clarification on any step?


Follow-up Questions:

  1. Would you like to compute the pp-value and decision for the hypothesis test?
  2. Should I explain how the correlation matrix is calculated in detail?
  3. Would you like to understand how the regression coefficients are computed from scratch?
  4. Do you want a step-by-step analysis of the test statistic formula?
  5. Should I provide a graph to visualize the correlations?

Tip:

When dealing with multiple regression, always examine the correlation matrix to assess multicollinearity before interpreting regression coefficients.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Regression Analysis
Correlation Analysis
Hypothesis Testing
Multiple Linear Regression

Formulas

Regression Equation: y = b0 + b1x1 + b2x2
Correlation Coefficient: r = Cov(x, y) / sqrt(Var(x) * Var(y))
Test Statistic for Correlation: t = r * sqrt(n - 2) / sqrt(1 - r^2)

Theorems

Least Squares Method
Properties of Correlation Coefficients
Student's t-distribution for Hypothesis Testing

Suitable Grade Level

Undergraduate (Statistics or Econometrics)