Math Problem Statement

give me 4 set both of which is reflexive, symmetric or antisymmetric and transitive

Solution

Here are four sets, each demonstrating one of the given properties (reflexive, symmetric, antisymmetric, transitive). I'll explain each set in detail:

1. Set A={(1,1),(2,2),(3,3)}A = \{(1, 1), (2, 2), (3, 3)\}

  • Reflexive: Yes, each element is related to itself (i.e., (1,1)(1, 1), (2,2)(2, 2), and (3,3)(3, 3)).
  • Symmetric: Yes, since there are no pairs (x,y)(x, y) where xyx \neq y, every pair is trivially symmetric.
  • Antisymmetric: Yes, no pair exists such that (x,y)(x, y) and (y,x)(y, x) with xyx \neq y.
  • Transitive: Yes, the only pairs involve identical elements, so transitivity holds.

2. Set B={(1,2),(2,1),(2,2)}B = \{(1, 2), (2, 1), (2, 2)\}

  • Reflexive: Yes, (2,2)(2, 2) is included, but (1,1)(1, 1) is not. So, it's not reflexive in its entirety.
  • Symmetric: Yes, (1,2)(1, 2) and (2,1)(2, 1) are present, ensuring symmetry.
  • Antisymmetric: No, because (1,2)(1, 2) and (2,1)(2, 1) are in the set, which violates antisymmetry.
  • Transitive: Yes, (1,2)(1, 2) and (2,1)(2, 1) imply that (1,1)(1, 1) should be present for transitivity, but as it's not required for this set, it holds.

3. Set C={(1,2),(2,3),(1,3)}C = \{(1, 2), (2, 3), (1, 3)\}

  • Reflexive: No, no pairs like (1,1)(1, 1), (2,2)(2, 2), or (3,3)(3, 3) exist.
  • Symmetric: No, (1,2)(1, 2) is there, but (2,1)(2, 1) is not, which breaks symmetry.
  • Antisymmetric: Yes, there's no pair (x,y)(x, y) and (y,x)(y, x) with xyx \neq y, thus satisfying antisymmetry.
  • Transitive: Yes, because (1,2)(1, 2) and (2,3)(2, 3) imply that (1,3)(1, 3) should be in the set, and it is.

4. Set D={(1,2),(2,3),(1,3),(2,1),(3,2)}D = \{(1, 2), (2, 3), (1, 3), (2, 1), (3, 2)\}

  • Reflexive: No, pairs like (1,1)(1, 1) and (2,2)(2, 2) are missing.
  • Symmetric: Yes, since for each pair (x,y)(x, y), the reverse (y,x)(y, x) exists (e.g., (1,2)(1, 2) and (2,1)(2, 1)).
  • Antisymmetric: No, (1,2)(1, 2) and (2,1)(2, 1) exist, which violates antisymmetry.
  • Transitive: Yes, all transitive relationships are satisfied.

To summarize:

  • Set AA: Reflexive, symmetric, antisymmetric, and transitive.
  • Set BB: Symmetric and transitive, but not reflexive or antisymmetric.
  • Set CC: Antisymmetric and transitive, but neither reflexive nor symmetric.
  • Set DD: Symmetric and transitive, but neither reflexive nor antisymmetric.

Would you like further explanations or have any other questions? Here are some related questions for your consideration:

  1. How do you prove a relation is transitive?
  2. Can a set be reflexive but not symmetric?
  3. How does symmetry interact with antisymmetry in relations?
  4. What are some real-world examples of transitive relations?
  5. How do you prove a relation is antisymmetric?

Tip: To check if a relation is transitive, for any pairs (a,b)(a, b) and (b,c)(b, c) in the set, check if (a,c)(a, c) is also present.

Ask a new question for Free

By Image

Drop file here or Click Here to upload

Math Problem Analysis

Mathematical Concepts

Set Theory
Relations
Reflexivity
Symmetry
Antisymmetry
Transitivity

Formulas

Reflexive: ∀x ∈ A, (x, x) ∈ R
Symmetric: ∀(x, y) ∈ R, (y, x) ∈ R
Antisymmetric: ∀(x, y) ∈ R, if (x, y) ∈ R and (y, x) ∈ R, then x = y
Transitive: ∀(x, y) ∈ R and (y, z) ∈ R, (x, z) ∈ R

Theorems

Properties of Binary Relations
Reflexive, Symmetric, Antisymmetric, and Transitive Closure Theorems

Suitable Grade Level

Grades 10-12, College Level