Math Problem Statement

Given the relation R={(2, 4), (4, 2)} on the set A={1, 2, 3, 4}

Which of the following is correct?

Points will be deducted for each incorrect response; however, negative scoring will not be applied.

Question 2 Select one or more:

Irreflexive, Not antisymmetric and Not transitive

Not reflexive, Not antisymmetric and transitive

Irreflexive, antisymmetric and Not transitive

Reflexive, Not antisymmetric and symmetric

Not reflexive, antisymmetric and transitive

Irreflexive, antisymmetric and transitive

None of the listed answers is correct.

Not reflexive, Not antisymmetric and Not transitive

Reflexive, Not antisymmetric and Not symmetric

Not reflexive, antisymmetric and symmetric   

Not reflexive, antisymmetric and Not transitive

Reflexive, antisymmetric and Not symmetric

Irreflexive, Not antisymmetric and transitive

Solution

To analyze the relation R={(2,4),(4,2)}R = \{(2, 4), (4, 2)\} on the set A={1,2,3,4}A = \{1, 2, 3, 4\}, let's examine its properties: reflexivity, irreflexivity, antisymmetry, symmetry, and transitivity.

1. Reflexivity:

A relation is reflexive if for every element aAa \in A, the pair (a,a)(a, a) is in RR.

  • Since RR does not contain any pairs like (1,1),(2,2),(3,3),(1, 1), (2, 2), (3, 3), or (4,4)(4, 4), the relation is not reflexive.

2. Irreflexivity:

A relation is irreflexive if for every element aAa \in A, the pair (a,a)(a, a) is not in RR.

  • As no pair of the form (a,a)(a, a) exists in RR, the relation is irreflexive.

3. Antisymmetry:

A relation is antisymmetric if for all a,bAa, b \in A, whenever (a,b)R(a, b) \in R and (b,a)R(b, a) \in R, it must be that a=ba = b.

  • Here, (2,4)(2, 4) and (4,2)(4, 2) are both in RR, but 242 \neq 4. Therefore, the relation is not antisymmetric.

4. Symmetry:

A relation is symmetric if for every (a,b)R(a, b) \in R, (b,a)(b, a) is also in RR.

  • Since (2,4)(2, 4) and (4,2)(4, 2) are both in RR, the relation is symmetric.

5. Transitivity:

A relation is transitive if whenever (a,b)R(a, b) \in R and (b,c)R(b, c) \in R, then (a,c)(a, c) must also be in RR.

  • For (2,4)(2, 4) and (4,2)(4, 2), there is no (2,2)(2, 2) in RR, nor does any other pair satisfy this condition. Thus, the relation is not transitive.

Conclusion:

Based on the analysis:

  • The relation is irreflexive (no (a,a)(a, a) pairs in RR).
  • The relation is not antisymmetric (since (2,4)(2, 4) and (4,2)(4, 2) are in RR).
  • The relation is not transitive.
  • The relation is symmetric.

The correct options are:

  • Irreflexive, Not antisymmetric and Not transitive
  • Not reflexive, Not antisymmetric and Not transitive

Would you like further details or have any questions? Here are some related questions:

  1. How is antisymmetry different from symmetry in relations?
  2. What are some examples of irreflexive relations in everyday life?
  3. How can we determine if a relation is an equivalence relation?
  4. What are some practical applications of transitive relations?
  5. Can a relation be both symmetric and antisymmetric? Why or why not?
  6. How does reflexivity relate to the concept of identity in mathematics?
  7. What happens if a relation is both reflexive and transitive?
  8. Can a non-reflexive relation be transitive?

Tip: When determining the properties of a relation, systematically check each property (reflexivity, symmetry, transitivity, etc.) to ensure a complete understanding.

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Math Problem Analysis

Mathematical Concepts

Relations
Reflexivity
Irreflexivity
Antisymmetry
Symmetry
Transitivity

Formulas

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Theorems

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Suitable Grade Level

College