To solve this question, we need to reflect the shaded triangle across the vertical line $x = 6$. Here's the step-by-step process:

1. Identify the vertices of the triangle: From the image, the coordinates of the vertices of the triangle appear to be approximately:

   • $(2, -5)$
   • $(4, -7)$
   • $(3, -3)$

2. Reflect the points: When reflecting across the line $x = 6$, the distance of each point from $x = 6$ will remain the same, but the new $x$-coordinate will be adjusted accordingly. The formula for reflecting a point $(x, y)$ is: $x' = 2 \times 6 - x, \quad y' = y$ Applying this formula to each vertex:

   • For $(2, -5)$:
     $x' = 2 \times 6 - 2 = 10, \, y' = -5$, so the new point is $(10, -5)$.
   • For $(4, -7)$:
     $x' = 2 \times 6 - 4 = 8, \, y' = -7$, so the new point is $(8, -7)$.
   • For $(3, -3)$:
     $x' = 2 \times 6 - 3 = 9, \, y' = -3$, so the new point is $(9, -3)$.

3. Draw the reflected triangle: Plot the new points $(10, -5)$, $(8, -7)$, and $(9, -3)$ on the grid. Connect these points to form the reflected triangle.

If you'd like, I can provide a visualization or further clarification of the process. Let me know!

Here are some follow-up questions:

1. What are the mathematical rules for reflecting shapes across vertical and horizontal lines?
2. How would you reflect a shape across the line $y = c$?
3. How can reflection properties help in understanding symmetry?
4. What is the significance of maintaining distances during reflections?
5. Can reflections be used to solve real-world problems involving symmetry?

Tip: Always check the reference line (e.g., $x = 6$) carefully to ensure accurate calculations.