Math Problem Statement

Complete the recursive formula of the arithmetic sequence [8, -5, -18, -31,\unicode{0x2026}].

[d(1)=]  

[d(n)=d(n-1)+] 

Solution

Let's work through the arithmetic sequence:

The sequence is:
8,5,18,31,8, -5, -18, -31, \dots

Step 1: Find the common difference (d)

To find the common difference, subtract any term from the next term in the sequence:

d=58=13d = -5 - 8 = -13 d=18(5)=13d = -18 - (-5) = -13 d=31(18)=13d = -31 - (-18) = -13

So, the common difference dd is 13-13.

Step 2: Define the recursive formula

For an arithmetic sequence, the recursive formula is:

d(1)=the first term of the sequenced(1) = \text{the first term of the sequence} d(n)=d(n1)+dd(n) = d(n-1) + d

Given the first term is 8 and the common difference is 13-13, we can write:

d(1)=8d(1) = 8 d(n)=d(n1)13forn>1d(n) = d(n-1) - 13 \quad \text{for} \quad n > 1

Final Answer:

  • d(1)=8d(1) = 8
  • d(n)=d(n1)13d(n) = d(n-1) - 13 for n>1n > 1

Would you like more details on this solution or have any questions?

Here are some related questions:

  1. How would you write the explicit formula for this arithmetic sequence?
  2. How do you find the nth term of an arithmetic sequence using the explicit formula?
  3. Can you apply the recursive formula to find the 5th term of this sequence?
  4. How does the common difference affect the behavior of an arithmetic sequence?
  5. How can the concept of arithmetic sequences be applied to real-life situations?

Tip: The recursive formula is especially useful for finding terms in a sequence when you know the previous term, but the explicit formula is faster for directly finding any term nn.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Recursive Formulas
Common Difference

Formulas

Recursive formula for an arithmetic sequence: d(n) = d(n-1) + d
First term: d(1) = initial term

Theorems

Recursive formula for arithmetic sequences

Suitable Grade Level

Grades 6-8