Math Problem Statement

13, 11, 9, 7, 5, 3, ... Find a recursive formula for this sequence that is valid for n>1.

Solution

The sequence provided is:
13,11,9,7,5,3,13, 11, 9, 7, 5, 3, \dots

This is a simple arithmetic sequence, where each term is obtained by subtracting 2 from the previous term.

To express the sequence recursively, we can define the general recursive formula as follows:

  1. Base case: The first term of the sequence is given as a1=13a_1 = 13.
  2. Recursive relation: Each subsequent term is obtained by subtracting 2 from the previous term, so for n>1n > 1: an=an12a_n = a_{n-1} - 2

Thus, the recursive formula for this sequence is:

a_1 = 13 \\ a_n = a_{n-1} - 2 \quad \text{for} \, n > 1 \end{cases}$$ This will generate the sequence: 13, 11, 9, 7, 5, 3, ... Would you like further clarification on any part of this process, or do you have additional questions? Here are 5 related questions for you: 1. How can you write the closed-form (non-recursive) formula for this arithmetic sequence? 2. What is the sum of the first 10 terms of this sequence? 3. How would the recursive formula change if the sequence was increasing instead of decreasing? 4. Can you find a recursive formula for a geometric sequence? 5. How would you identify the common difference in any arithmetic sequence? **Tip:** To identify a recursive formula for a sequence, first look for a consistent pattern (like adding or subtracting the same value) between terms.

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Math Problem Analysis

Mathematical Concepts

Arithmetic Sequences
Recursion

Formulas

Recursive formula: a_n = a_{n-1} - 2

Theorems

Arithmetic sequence properties

Suitable Grade Level

Grades 6-8