Math Problem Statement

Assume a number sequence a0, a1, a2, a3, a4,... satisfies the following recursion: an = 2an-1 + 4an-2 for n >= 2. Find the general form of the n-th term an.

Solution

The given recurrence relation is:

an=2an1+4an2a_n = 2a_{n-1} + 4a_{n-2}

for n2n \geq 2. We need to find the general form of ana_n.

Step 1: Solve the characteristic equation

This is a linear recurrence relation with constant coefficients, so we begin by solving the associated characteristic equation. The recurrence relation can be transformed into the characteristic equation by assuming a solution of the form an=rna_n = r^n.

Substitute an=rna_n = r^n, an1=rn1a_{n-1} = r^{n-1}, and an2=rn2a_{n-2} = r^{n-2} into the recurrence relation:

rn=2rn1+4rn2r^n = 2r^{n-1} + 4r^{n-2}

Divide through by rn2r^{n-2}:

r2=2r+4r^2 = 2r + 4

Rearrange this to form a quadratic equation:

r22r4=0r^2 - 2r - 4 = 0

Step 2: Solve the quadratic equation

Now solve the quadratic equation r22r4=0r^2 - 2r - 4 = 0 using the quadratic formula:

r=(2)±(2)24(1)(4)2(1)r = \frac{-(-2) \pm \sqrt{(-2)^2 - 4(1)(-4)}}{2(1)}

r=2±4+162=2±202r = \frac{2 \pm \sqrt{4 + 16}}{2} = \frac{2 \pm \sqrt{20}}{2}

r=2±252r = \frac{2 \pm 2\sqrt{5}}{2}

r=1±5r = 1 \pm \sqrt{5}

So, the two roots of the characteristic equation are:

r1=1+5,r2=15r_1 = 1 + \sqrt{5}, \quad r_2 = 1 - \sqrt{5}

Step 3: General solution

Since the characteristic equation has distinct real roots, the general solution to the recurrence relation is of the form:

an=C1(1+5)n+C2(15)na_n = C_1(1 + \sqrt{5})^n + C_2(1 - \sqrt{5})^n

where C1C_1 and C2C_2 are constants determined by the initial conditions.

If you have specific initial values for a0a_0 and a1a_1, we can proceed to find C1C_1 and C2C_2.

Would you like to provide the initial conditions, or should I continue with the general solution?


Feel free to ask if you need more details on any step. Here are some related questions:

  1. What happens if the characteristic equation has complex roots?
  2. How would you find the constants C1C_1 and C2C_2?
  3. How can recurrence relations be solved using matrix methods?
  4. Can you solve recurrence relations with variable coefficients similarly?
  5. What are the applications of solving such recurrence relations in computer science?

Tip: Always check the characteristic equation first when solving linear recurrence relations with constant coefficients.

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Math Problem Analysis

Mathematical Concepts

Recurrence Relations
Algebra
Characteristic Equations

Formulas

Recurrence relation: an = 2an-1 + 4an-2
Characteristic equation: r^2 = 2r + 4
Quadratic equation: r^2 - 2r - 4 = 0
Quadratic formula: r = (-b ± √(b^2 - 4ac)) / 2a

Theorems

Quadratic Formula

Suitable Grade Level

Grades 11-12, College Level