To solve this, we will use the formula for the perimeter of a rectangle:

$\text{Perimeter} = 2(\text{Length} + \text{Width})$

Step 1: Define the variables

• Let the width of the soccer field be $w$ meters.
• The length of the soccer field is 100 meters greater than its width, so the length will be $w + 100$ meters.

Step 2: Set up the perimeter equation

The total perimeter is given as 560 meters, so:

$2(\text{Length} + \text{Width}) = 560$

Substitute the expressions for length and width:

$2((w + 100) + w) = 560$

Step 3: Simplify and solve for $w$

$2(2w + 100) = 560$

$4w + 200 = 560$

Now, subtract 200 from both sides:

$4w = 360$

Finally, divide by 4:

$w = 90$

Step 4: Find the length

Since the length is 100 meters greater than the width:

$\text{Length} = w + 100 = 90 + 100 = 190$

Solution:

• Width = 90 meters
• Length = 190 meters

Would you like further details or have any questions?

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Here are 5 related questions to expand on this concept:

1. How would the dimensions change if the perimeter was 600 m instead of 560 m?
2. Can you find the area of the soccer field based on these dimensions?
3. What would the width be if the length was 50 m greater instead of 100 m?
4. If you doubled the width, what would the new perimeter be?
5. How would the length and width be affected if the field were square?

Tip: Always double-check your equations for accuracy by plugging the final solution back into the original equation!