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Let's break down the problem:

- The length of a new rectangular playing field is **5 yards longer than double the width**.
- The perimeter of the field is **250 yards**.
- You need to find the dimensions (the width and length).

### Let’s define the variables:
- Let \( w \) be the width of the rectangular field in yards.
- The length of the field is \( 2w + 5 \) yards (because it's 5 yards longer than double the width).

### Formula for the perimeter of a rectangle:
The perimeter \( P \) of a rectangle is given by:
\[
P = 2 \times (\text{length} + \text{width})
\]

Substitute the given perimeter (250 yards) and the expressions for length and width:
\[
250 = 2 \times \left( (2w + 5) + w \right)
\]

### Solve the equation:
First, simplify the equation:
\[
250 = 2 \times (3w + 5)
\]
\[
250 = 6w + 10
\]
Subtract 10 from both sides:
\[
240 = 6w
\]
Now divide both sides by 6:
\[
w = 40
\]

### Find the length:
Substitute \( w = 40 \) into the expression for the length:
\[
\text{Length} = 2w + 5 = 2(40) + 5 = 80 + 5 = 85
\]

### Final dimensions:
- Width = **40 yards**
- Length = **85 yards**

Would you like more details or have any questions about this solution?

Here are 5 related questions:
1. How would the dimensions change if the perimeter were 300 yards?
2. What would happen if the length were triple the width instead of double plus 5 yards?
3. Can you solve this problem using the area of the rectangle?
4. How does changing the perimeter affect the relationship between width and length?
5. What other real-world problems could use a similar setup for their solution?

**Tip:** Always double-check that your variables correctly match the conditions given in word problems.

The length of a new rectangular playing field is 5 yards longer than double the width. If the perimeter of the rectangular playing field is 250 yards, what are its dimensions?

Learn how to find the dimensions of a rectangular playing field where the length is 5 yards longer than double the width and the perimeter is 250 yards. This problem covers key algebraic concepts, including perimeter calculation and solving linear equations. Suitable for students in Grades 8-10.

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