Let's solve this problem step by step.

Problem Recap:

• Length of the rectangle = 5 cm longer than twice its width.
• Perimeter of the rectangle = 88 cm.

We need to find the width of the rectangle.

Step 1: Define variables.

• Let the width of the rectangle be $w$ (in cm).
• Then, the length of the rectangle will be $2w + 5$ cm (since it's 5 cm longer than twice the width).

Step 2: Use the perimeter formula for a rectangle.

The perimeter $P$ of a rectangle is given by: $P = 2 \times (\text{length} + \text{width})$

Substitute the given perimeter (88 cm) and the expressions for length and width: $88 = 2 \times ((2w + 5) + w)$

Step 3: Simplify and solve for $w$.

First, expand the equation: $88 = 2 \times (3w + 5)$ $88 = 6w + 10$

Now, subtract 10 from both sides: $78 = 6w$

Finally, divide both sides by 6: $w = \frac{78}{6} = 13$

Conclusion:

The width of the rectangle is 13 cm.

Would you like more details on any step?

Related Questions:

1. What would the length of the rectangle be, given this width?
2. How would the width change if the perimeter were different?
3. Can you derive the formula for the area of this rectangle?
4. How does changing the constant 5 cm affect the solution?
5. Can you explain why the perimeter formula is doubled?

Tip:

Always double-check your solution by substituting the values back into the original equation!