Let's solve the two parts of the problem in the image step by step:

(a) Perimeter of the rectangular parking lot

The problem states:

• Perimeter $P = 362$ meters
• Length $l = 96$ meters
• We need to find the width $w$.

The formula for the perimeter of a rectangle is: $P = 2(l + w)$ Substituting the known values: $362 = 2(96 + w)$ Now, solve for $w$:

1. Divide both sides by 2: $181 = 96 + w$
2. Subtract 96 from both sides: $w = 181 - 96 = 85 \text{ meters}$ So, the width of the parking lot is 85 meters.

(b) Area of the rectangular pool

The problem states:

• Area $A = 71.44$ square meters
• Width $w = 76$ meters
• We need to find the length $l$.

The formula for the area of a rectangle is: $A = l \times w$ Substitute the known values: $71.44 = l \times 76$ Now solve for $l$:

1. Divide both sides by 76: $l = \frac{71.44}{76} = 0.94 \text{ meters}$ So, the length of the pool is 0.94 meters.

Let me know if you'd like more details or have any questions.

Follow-up questions:

1. How do we calculate the perimeter of a rectangle with different dimensions?
2. What happens to the perimeter if both the length and width are doubled?
3. How can we find the diagonal of a rectangle given its length and width?
4. How is the formula for the area of a rectangle derived?
5. How does changing the width affect the area of a rectangle?

Tip: For any rectangle, if you know two sides (length and width), you can always find the perimeter and area easily using basic formulas.