Math Problem Statement

Find the perimeter and area of the rectangle with length 17 meters and width 8 meters.

Solution

To find the perimeter and area of the rectangle shown in the image, we can use the following formulas based on the provided dimensions.

Given:

  • Length, l=17l = 17 meters
  • Width, w=8w = 8 meters

Formulas:

  1. Perimeter of a Rectangle: P=2×(l+w)P = 2 \times (l + w)
  2. Area of a Rectangle: A=l×wA = l \times w

Solution:

  1. Perimeter: P=2×(17+8)=2×25=50mP = 2 \times (17 + 8) = 2 \times 25 = 50 \, \text{m}

  2. Area: A=17×8=136m2A = 17 \times 8 = 136 \, \text{m}^2

Answer:

  • The perimeter is 50m50 \, \text{m}.
  • The area is 136m2136 \, \text{m}^2.

Would you like more details or have any questions?

Here are some related questions:

  1. What is the formula for the perimeter of a square?
  2. How would the area change if the width were doubled?
  3. What is the relationship between the perimeter and the area of a rectangle?
  4. How can you calculate the length if you know the perimeter and the width?
  5. How does changing the length affect the perimeter?

Tip: The area of a rectangle grows proportionally with either dimension, so doubling one dimension doubles the area.

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Math Problem Analysis

Mathematical Concepts

Geometry
Perimeter
Area

Formulas

Perimeter of a rectangle: P = 2 × (length + width)
Area of a rectangle: A = length × width

Theorems

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Suitable Grade Level

Grades 4-6