To create an equation for the given problem, we need to analyze the situation carefully.

1. The perimeter of a rectangle is given by the formula:
   $P = 2(L + W)$ where $L$ is the length and $W$ is the width.

2. We are given:

   • The perimeter $P = 24$ inches
   • The length $L = 2$ cm.

However, there's a unit mismatch since the perimeter is in inches, and the length is in centimeters. To proceed, we must convert one unit to the other.

Conversion:

1 cm = 0.3937 inches.
Thus, $L = 2 \ \text{cm} \times 0.3937 \approx 0.7874 \ \text{inches}$.

Substituting into the formula:

$24 = 2(0.7874 + W)$

Simplify and solve for $W$ (the width):

$24 = 2(0.7874) + 2W$

$24 = 1.5748 + 2W$

$2W = 24 - 1.5748$

$2W = 22.4252$

$W = \frac{22.4252}{2}$

$W \approx 11.2126 \ \text{inches}.$

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Final Equation:

The equation for this problem is:
$24 = 2(0.7874 + W)$ Where $W$ is the width of the rectangle in inches.

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Let me know if you would like the width solved further, or have questions!

Related Questions:

1. What is the width of the rectangle in centimeters?
2. How do you convert units between inches and centimeters?
3. If the length was doubled, what would the new perimeter be?
4. What is the area of the rectangle in square inches?
5. Can you write an equation where both length and width are variables?

Tip: Always ensure units are consistent before setting up an equation!