To solve for the length of the rectangle, we can use the equation for the perimeter of a rectangle, which is given by:

$2 \times \text{length} + 2 \times \text{width} = 48$

We are given:

• Width = 3.6 cm
• Perimeter = 48 cm

Let's plug the width into the equation:

$2 \times \text{length} + 2 \times 3.6 = 48$

Simplify the equation:

$2 \times \text{length} + 7.2 = 48$

Now, subtract 7.2 from both sides:

$2 \times \text{length} = 48 - 7.2$ $2 \times \text{length} = 40.8$

Next, divide both sides by 2:

$\text{length} = \frac{40.8}{2} = 20.4 \, \text{cm}$

So, the length of the rectangle is 20.4 cm.

Would you like more details, or have any questions?

Here are 5 related questions for further practice:

1. What would the length be if the width were 4 cm?
2. How would you calculate the area of this rectangle?
3. If the perimeter increased to 50 cm, how would that affect the length?
4. What is the formula for the perimeter of other polygons?
5. How do you find the diagonal of a rectangle given its length and width?

Tip: Remember that the formula for the perimeter of a rectangle is always $2 \times (\text{length} + \text{width})$.