To solve the problem, we use the formula for the perimeter of a rectangle:

$P = 2 \times (\text{length} + \text{width})$

Step 1: Define variables

Let the width of the rectangle be $w$ and the length be $l$.

Given that: $l = 5w$ $P = 108 \, \text{yd}$

Substituting into the formula: $108 = 2 \times (l + w)$

Step 2: Substitute $l = 5w$ into the equation

$108 = 2 \times (5w + w)$

Simplify: $108 = 2 \times 6w$

$108 = 12w$

Step 3: Solve for $w$

$w = \frac{108}{12} = 9 \, \text{yd}$

Step 4: Solve for $l$

Using $l = 5w$: $l = 5 \times 9 = 45 \, \text{yd}$

Final Answer:

$\text{Width} = 9 \, \text{yd}$ $\text{Length} = 45 \, \text{yd}$

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Let me know if you'd like a detailed explanation of the steps or have further questions. Here are 5 related questions for further practice:

1. What is the area of this rectangle?
2. If the width of the rectangle were doubled, what would the new perimeter be?
3. What is the ratio of the length to the width of this rectangle?
4. How would the perimeter change if both the length and width were halved?
5. What is the diagonal length of the rectangle?

Tip: Always express relationships between dimensions algebraically before solving equations.