To solve this problem, let's break down the information provided.

1. Let $w$ represent the width of the rectangle in yards.
2. The length is 3 yards longer than the width, so the length will be $w + 3$.
3. The perimeter is given as 58 yards. The perimeter formula for a rectangle is: $P = 2 \times (\text{length} + \text{width})$ Substituting in the values we have: $58 = 2 \times ((w + 3) + w)$
4. Simplify and solve for $w$: $58 = 2 \times (2w + 3)$ $58 = 4w + 6$ $52 = 4w$ $w = 13$
5. Now, we know the width is $13$ yards. To find the length, substitute $w$ back into the expression for the length: $\text{Length} = w + 3 = 13 + 3 = 16$

Answer:

• Width = 13 yards
• Length = 16 yards

Would you like further details, or have any questions?

Here are some related questions you might find helpful:

1. What would happen to the perimeter if the width were increased by 2 yards?
2. How would you find the area of the rectangle given these dimensions?
3. If the perimeter was doubled, what would be the new width and length?
4. How does changing the length affect the perimeter when the width remains constant?
5. Can you find the dimensions of a rectangle with a perimeter of 100 yards where the length is twice the width?

Tip: When solving problems with rectangles, always remember that the perimeter formula involves multiplying by 2, as there are two lengths and two widths.