The problem states:

The area $A$ of a triangle is represented by the formula:

$A = \frac{1}{2} b h$

where $b$ is the base and $h$ is the height. The task is to rewrite this formula in a way that makes it easy to find the base $b$ if we know the area $A$ and the height $h$.

To isolate $b$, we can rearrange the formula as follows:

1. Start with the formula for the area of a triangle: $A = \frac{1}{2} b h$

2. Multiply both sides by 2 to eliminate the fraction: $2A = b h$

3. Divide both sides by $h$ to solve for $b$: $b = \frac{2A}{h}$

So, the equation that makes it easy to find the base $b$ given the area $A$ and height $h$ is:

$b = \frac{2A}{h}$

Would you like a further breakdown of the solution steps or have any other questions?

Here are some related questions you might find useful:

1. How do you rearrange a formula to isolate a variable?
2. How does changing the height $h$ affect the base $b$ if the area is constant?
3. What happens to the value of $b$ if both $A$ and $h$ double?
4. How can we use this formula to check if a given triangle has the correct dimensions for a specific area?
5. How does this formula relate to the area of other shapes?

Tip: When rearranging equations, always perform the same operation on both sides to maintain equality.