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The problem states:

The area \( A \) of a triangle is represented by the formula:

\[
A = \frac{1}{2} b h
\]

where \( b \) is the base and \( h \) is the height. The task is to rewrite this formula in a way that makes it easy to find the base \( b \) if we know the area \( A \) and the height \( h \).

To isolate \( b \), we can rearrange the formula as follows:

1. Start with the formula for the area of a triangle:
   \[
   A = \frac{1}{2} b h
   \]

2. Multiply both sides by 2 to eliminate the fraction:
   \[
   2A = b h
   \]

3. Divide both sides by \( h \) to solve for \( b \):
   \[
   b = \frac{2A}{h}
   \]

So, the equation that makes it easy to find the base \( b \) given the area \( A \) and height \( h \) is:

\[
b = \frac{2A}{h}
\]

Would you like a further breakdown of the solution steps or have any other questions?

Here are some related questions you might find useful:

1. How do you rearrange a formula to isolate a variable?
2. How does changing the height \( h \) affect the base \( b \) if the area is constant?
3. What happens to the value of \( b \) if both \( A \) and \( h \) double?
4. How can we use this formula to check if a given triangle has the correct dimensions for a specific area?
5. How does this formula relate to the area of other shapes?

**Tip:** When rearranging equations, always perform the same operation on both sides to maintain equality.

The area A of a triangle is represented by the formula A = 1/2 * b * h where b is the base and h is the height. Write an equation that makes it easy to find the base if we know the area and the height.

Learn how to rearrange the area formula of a triangle to solve for the base, given the area and height. This tutorial provides a step-by-step solution using algebraic techniques suitable for students in Grades 6-8.

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