Math Problem Statement
Rationalize the denominator
Solution
Rationalizing the denominator means eliminating any irrational numbers, like square roots, from the denominator of a fraction. We usually achieve this by multiplying both the numerator and the denominator by a term that will make the denominator rational.
Here's a general approach based on the type of denominator:
1. Denominator with a Single Square Root
If the denominator has a single square root, like in :
- Multiply both the numerator and the denominator by to get:
2. Denominator with a Binomial Involving Square Roots
If the denominator is a binomial with a square root, like :
- Multiply both the numerator and the denominator by the conjugate of the denominator, which is :
- This results in a rational denominator because the difference of squares is applied.
Would you like a specific example solved, or do you have a particular problem in mind?
Follow-up Questions:
- How do you rationalize a denominator with multiple square roots?
- What is the conjugate, and why is it useful in rationalization?
- How does rationalization change if cube roots are involved?
- How would you rationalize a denominator with both square roots and variables?
- Why is rationalizing the denominator often required in mathematical expressions?
Tip: Conjugates are especially helpful when dealing with binomials, as they allow simplification through the difference of squares formula.
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Math Problem Analysis
Mathematical Concepts
Algebra
Rationalization
Radicals
Square Roots
Formulas
For \( \frac{a}{\sqrt{b}} \), multiply by \( \frac{\sqrt{b}}{\sqrt{b}} \): \( \frac{a \sqrt{b}}{b} \)
For \( \frac{a}{b + \sqrt{c}} \), multiply by conjugate \( \frac{b - \sqrt{c}}{b - \sqrt{c}} \): \( \frac{a(b - \sqrt{c})}{b^2 - c} \)
Theorems
Difference of Squares Theorem
Suitable Grade Level
Grades 9-11