Math Problem Statement

Given that a/b = 2/5 and b/c = 3/4, find a:b:c.

Solution

The problem given is:

ab=25andbc=34\frac{a}{b} = \frac{2}{5} \quad \text{and} \quad \frac{b}{c} = \frac{3}{4}

We need to find the ratio a:b:ca : b : c.

Step 1: Express aa in terms of bb

From the first equation, we have: ab=25    a=25b\frac{a}{b} = \frac{2}{5} \implies a = \frac{2}{5}b

Step 2: Express bb in terms of cc

From the second equation, we have: bc=34    b=34c\frac{b}{c} = \frac{3}{4} \implies b = \frac{3}{4}c

Step 3: Substitute bb in terms of cc into the expression for aa

Now, substitute b=34cb = \frac{3}{4}c into the expression a=25ba = \frac{2}{5}b: a=25×34c=620c=310ca = \frac{2}{5} \times \frac{3}{4}c = \frac{6}{20}c = \frac{3}{10}c

Step 4: Find the ratio a:b:ca : b : c

Now we have the following:

  • a=310ca = \frac{3}{10}c
  • b=34cb = \frac{3}{4}c
  • c=cc = c

To express the ratio a:b:ca : b : c, we need to make sure all the terms are proportional to cc.

The least common denominator between 10 and 4 is 20. So we rewrite the terms as: a=310c=620c,b=34c=1520c,c=2020ca = \frac{3}{10}c = \frac{6}{20}c, \quad b = \frac{3}{4}c = \frac{15}{20}c, \quad c = \frac{20}{20}c

Thus, the ratio is: a:b:c=6:15:20a : b : c = 6 : 15 : 20

Would you like further clarification or additional details?

Here are five related questions to deepen your understanding:

  1. How do we solve ratios when more than two variables are involved?
  2. What happens if the ratios involve square roots or exponents?
  3. How can we simplify ratios with negative values or decimals?
  4. Can we solve for individual values of aa, bb, or cc if given additional information?
  5. How are proportions useful in real-life applications, such as scaling models or recipes?

Tip: When solving ratio problems, it's helpful to find the least common denominator to express all terms in the same form.

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Math Problem Analysis

Mathematical Concepts

Ratios
Proportions
Algebra

Formulas

a/b = 2/5
b/c = 3/4
Cross-multiplication to solve ratios

Theorems

Proportion theorem

Suitable Grade Level

Grades 7-9